Given that When a certain coin is flipped, the probability of heads is 0.5 and the coin is flipped 6 times. And we need to find what is the probability that there are exactly 3 heads?Now there are six places to fill as shown below
_ _ _ _ _ _
We need to get 3 Heads and 3 Tails.
Now lets find out the slots out of these 6 in which 3 heads will go.
We can find that using 6C3 = \(\frac{6!}{3!*(6-3)!}\) = \(\frac{6!}{3!*3!}\) = \(\frac{6*5*4*3*2*1}{3*2*1*3*2*1}\) = 20 ways
Now, in the remaining slots we will have Tails. So we can get 3H and 3T in 20 ways
We know that probability of getting a head, P(H), = Probability of getting a Tail, P(T) = \(\frac{1}{2}\)
=> Probability of getting 3H and 3T = Number of ways * P(H) * P(H) * P(H) * P(T) * P(T) * P(T) = 20 * \(\frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2}\) = \(\frac{5}{16}\)
So,
Answer will be CHope it helps!
Watch the following video to learn How to Solve Probability with Coin Toss Problems