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505-555 Level|   Functions and Custom Characters|   Word Problems|                              
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nalinnair
When the wind speed is 9 miles per hour, the wind-chill factor w is given by w = -17.366 + 1.19t, where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit

In such Qs, it is possible on many occasions, May not be here, that one of the statements gives you a value which will give you a range that will suffice.. May not be here

w = -17.366 + 1.19t....
(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.
w = -17.366 + 1.19t so here w > -17.366 + 1.19*10 = -17.366+11.9= -6.abc.. so A value belw 0 is also possible and also above0.... ....
Insuff..

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit
w = -17.366 + 1.19t so here w < -17.366 + 1.19*20 = -17.366+23.8= 6.xyz.. so A value below 0 is also possible and also above 0.... ....
Insuff..

Combined
again the range is -6 to 6..
Insuff
E
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Hi,
Let's see when W=0

17.366=1.19t
t= \(\frac{17.366}{1.19}\)
rounding the numerator and denominator we have

t= \(\frac{17.4}{1.2}\)
t= 14.5 (approx)
So if t> 14.5 w will be >0

Now we need to know if 14.5<t

Statement 1 : NS
Statement 2 : NS

Combined No new information

Hence Choice E
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nalinnair
When the wind speed is 9 miles per hour, the wind-chill factor w is given by

\(w = -17.366 + 1.19t\),

where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit


what is the significance of the wind speed in this question?
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nalinnair
When the wind speed is 9 miles per hour, the wind-chill factor w is given by

\(w = -17.366 + 1.19t\),

where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit


what is the significance of the wind speed in this question?

Nothing, I believe it's there to confuse so that ppl will spare few seconds on it's usability and waste time.
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nalinnair
When the wind speed is 9 miles per hour, the wind-chill factor w is given by

\(w = -17.366 + 1.19t\),

where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit

\(w = -17.366 + 1.19t\)

(1) If the temperature was greater than 10 degrees Fahrenheit, if t = 11 then the wind chill will be less than 0. if t = 20 then the wind chill greater than 0. INSUFFICIENT.

(2) If temperature was less than 20 degrees Fahrenheit, if t = 1 then wind chill will be less than 0. if t = 19, then wind chill will be greater than 0. INSUFFICIENT.

(1&2) Combined, the temperature will be between 10 and 20 degrees Fahrenheit. If t = 11, then wind chill be be less than 0. If t = 19, then wind chill will be greater than 0. INSUFFICIENT.

Answer is E.
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nalinnair
When the wind speed is 9 miles per hour, the wind-chill factor w is given by

\(w = -17.366 + 1.19t\),

where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit

(1) If t=12, t=20 The answer will be Yes and No; Insufficient.

(2) t can be 1 t can be 19, The answer will be Yes and No; Insufficient.

Considering both:
If t=12, t=19 The answer will be Yes and No; Insufficient.

The answer is E
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Given:When the wind speed is 9 miles per hour, the wind-chill factor w is given by

\(w = -17.366 + 1.19t\),

where t is the temperature in degrees Fahrenheit.

Asked: If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.
w = -17.366 + 1.19t ; where t>10 : Let t = 10 + x
w = - 17.366 + 11.9 + 1.19x
When t = 11; w < 0
But when t = 20; w>0
NOT SUFFICIENT

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit
w = -17.366 + 1.19t ; where t>10 : Let t = 20 - y
w = - 17.366 + 23.8 - 1.19y
When t = 20; w > 0
But when t = 0; w<0
NOT SUFFICIENT

(1) + (2)
(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.
(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit
w = -17.366 + 1.19t
When t = 11; w < 0
But when t = 20; w>0
NOT SUFFICIENT

IMO E
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­I worked with the question stem first to determine that 1.19t > 17.366 if we have to have w>0 . 

This means that t> 8683/595. Since I did not want to get into calculations, I apprxoimated the values to be 8600/600 which is approx 14. 

True, I may have to get back to a more precise answer later, but seeing the statements given, i realised that it may not be necessary. 

Solving the statements have been explained well in this forum by other people. 

Hope this helps you... 
 
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