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# When the wind speed is 9 miles per hour, the wind-chill factor w is

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When the wind speed is 9 miles per hour, the wind-chill factor w is  [#permalink]

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23 May 2016, 03:35
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Difficulty:

25% (medium)

Question Stats:

72% (01:33) correct 28% (01:11) wrong based on 264 sessions

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When the wind speed is 9 miles per hour, the wind-chill factor w is given by

$$w = -17.366 + 1.19t$$,

where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit
Math Expert
Joined: 02 Aug 2009
Posts: 6521
Re: When the wind speed is 9 miles per hour, the wind-chill factor w is  [#permalink]

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23 May 2016, 05:27
1
nalinnair wrote:
When the wind speed is 9 miles per hour, the wind-chill factor w is given by w = -17.366 + 1.19t, where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit

In such Qs, it is possible on many occasions, May not be here, that one of the statements gives you a value which will give you a range that will suffice.. May not be here

w = -17.366 + 1.19t....
(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.
w = -17.366 + 1.19t so here w > -17.366 + 1.19*10 = -17.366+11.9= -6.abc.. so A value belw 0 is also possible and also above0.... ....
Insuff..

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit
w = -17.366 + 1.19t so here w < -17.366 + 1.19*20 = -17.366+23.8= 6.xyz.. so A value below 0 is also possible and also above 0.... ....
Insuff..

Combined
again the range is -6 to 6..
Insuff
E
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Re: When the wind speed is 9 miles per hour, the wind-chill factor w is  [#permalink]

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20 Dec 2017, 08:52
nalinnair wrote:
When the wind speed is 9 miles per hour, the wind-chill factor w is given by w = -17.366 + 1.19t, where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit

Given
=> w=-17.366+1.19t Is w>0

Now for 'w>0'
=> (-17.366+1.19t) should be >0
=> (-17.366+1.19t)>0
=> 1.19t>17.366
=> t>17.366/1.19 or
=> t>173.66/11.9 or
=> t>173.66/12
=> t>14

So if t>14 then w>0

Statement 1 t>10 therefore 2 scenario
a)if 10<t<14 then w<0
b)if t>14 then w>0
Since NO unique sol. Therefore NOT sufficient

Statement 2 t<20 therefore 2 scenario
a) if 14<t<20 then w>0
b) if t<14 then w<0
Since NO unique sol. Therefore NOT sufficient

BOTH 1 & 2
from Stat 1 t>10
from stat 2 t<20
Therefore 10<t<20
AGAIN 2 scenario.Therefore NOT sufficient

Therefore "E"

Thanks
Re: When the wind speed is 9 miles per hour, the wind-chill factor w is &nbs [#permalink] 20 Dec 2017, 08:52
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# When the wind speed is 9 miles per hour, the wind-chill factor w is

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