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Current Student B
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Joined: 09 Jan 2016
Posts: 117
Location: Hong Kong
GMAT 1: 750 Q50 V41 GPA: 3.52
When the wind speed is 9 miles per hour, the wind-chill factor w is  [#permalink]

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Difficulty:   25% (medium)

Question Stats: 76% (01:50) correct 24% (01:36) wrong based on 635 sessions

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When the wind speed is 9 miles per hour, the wind-chill factor w is given by

$$w = -17.366 + 1.19t$$,

where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit
Math Expert V
Joined: 02 Aug 2009
Posts: 7984
Re: When the wind speed is 9 miles per hour, the wind-chill factor w is  [#permalink]

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nalinnair wrote:
When the wind speed is 9 miles per hour, the wind-chill factor w is given by w = -17.366 + 1.19t, where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit

In such Qs, it is possible on many occasions, May not be here, that one of the statements gives you a value which will give you a range that will suffice.. May not be here

w = -17.366 + 1.19t....
(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.
w = -17.366 + 1.19t so here w > -17.366 + 1.19*10 = -17.366+11.9= -6.abc.. so A value belw 0 is also possible and also above0.... ....
Insuff..

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit
w = -17.366 + 1.19t so here w < -17.366 + 1.19*20 = -17.366+23.8= 6.xyz.. so A value below 0 is also possible and also above 0.... ....
Insuff..

Combined
again the range is -6 to 6..
Insuff
E
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Joined: 27 Apr 2015
Posts: 39
GMAT 1: 370 Q29 V13 Re: When the wind speed is 9 miles per hour, the wind-chill factor w is  [#permalink]

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nalinnair wrote:
When the wind speed is 9 miles per hour, the wind-chill factor w is given by w = -17.366 + 1.19t, where t is the temperature in degrees Fahrenheit. If at noon yesterday the wind speed was 9 miles per hour, was the wind-chill factor greater than 0 ?

(1) The temperature at noon yesterday was greater than 10 degrees Fahrenheit.

(2) The temperature at noon yesterday was less than 20 degrees Fahrenheit

Given
=> w=-17.366+1.19t Is w>0

Now for 'w>0'
=> (-17.366+1.19t) should be >0
=> (-17.366+1.19t)>0
=> 1.19t>17.366
=> t>17.366/1.19 or
=> t>173.66/11.9 or
=> t>173.66/12
=> t>14

So if t>14 then w>0

Statement 1 t>10 therefore 2 scenario
a)if 10<t<14 then w<0
b)if t>14 then w>0
Since NO unique sol. Therefore NOT sufficient

Statement 2 t<20 therefore 2 scenario
a) if 14<t<20 then w>0
b) if t<14 then w<0
Since NO unique sol. Therefore NOT sufficient

BOTH 1 & 2
from Stat 1 t>10
from stat 2 t<20
Therefore 10<t<20
AGAIN 2 scenario.Therefore NOT sufficient

Therefore "E"

Thanks
Senior Manager  P
Joined: 10 Apr 2018
Posts: 266
Location: United States (NC)
Re: When the wind speed is 9 miles per hour, the wind-chill factor w is  [#permalink]

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Hi,
Let's see when W=0

17.366=1.19t
t= $$\frac{17.366}{1.19}$$
rounding the numerator and denominator we have

t= $$\frac{17.4}{1.2}$$
t= 14.5 (approx)
So if t> 14.5 w will be >0

Now we need to know if 14.5<t

Statement 1 : NS
Statement 2 : NS

Combined No new information

Hence Choice E
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~You Just Can't beat the person who never gives up~ Babe Ruth Re: When the wind speed is 9 miles per hour, the wind-chill factor w is   [#permalink] 23 Apr 2019, 17:21
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