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31 May 2019, 11:00
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33% (03:03) correct
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1 unit of x% alcohol is mixed with 3 units of y% alcohol to give 60% alcohol. If x > y > 0, how many integer values can x take?
A. 10
B. 20
C. 35
D. 13
E. 30
A. 10
B. 20
C. 35
D. 13
E. 30
31 May 2019, 12:39
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x.........y
....60....
1.........3
\(\frac{x-60}{60-y}\)=3/1
x+3y=240...(1)
x=240-3y=3(80-y)
We have 2 constraints
1. x=<100
2. x>y
Also, x will be a multiple of 3
x can be 99,96.....63
At x=60, y=60....Hence x can't take value equal to 60 or lower than 60.
Total number of integer values x can take= [\(\frac{99-63}{3}\)]+1=13
....60....
1.........3
\(\frac{x-60}{60-y}\)=3/1
x+3y=240...(1)
x=240-3y=3(80-y)
We have 2 constraints
1. x=<100
2. x>y
Also, x will be a multiple of 3
x can be 99,96.....63
At x=60, y=60....Hence x can't take value equal to 60 or lower than 60.
Total number of integer values x can take= [\(\frac{99-63}{3}\)]+1=13
DisciplinedPrep
1 unit of x% alcohol is mixed with 3 units of y% alcohol to give 60% alcohol. If x > y, how many integer values can x take?
A. 10
B. 20
C. 35
D. 13
E. 30
A. 10
B. 20
C. 35
D. 13
E. 30
General Discussion
pulak1988
Joined: 15 Jan 2019
Last visit: 09 Sep 2020
Posts: 50
Own Kudos:
Given Kudos: 249
Location: India
Schools: ISB '20 IIMA Rotman '22 GMBA '21 (S)
GMAT 1: 650 Q42 V38
GPA: 4
31 May 2019, 20:43
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nick1816
x.........y
....60....
1.........3
\(\frac{x-60}{60-y}\)=3/1
x+3y=240...(1)
x=240-3y=3(80-y)
We have 2 constraints
1. x=<100
2. x>y
Also, x will be a multiple of 3
x can be 99,96.....63
At x=60, y=60....Hence x can't take value equal to 60 or lower than 60.
Total number of integer values x can take= [\(\frac{99-63}{3}\)]+1=13
....60....
1.........3
\(\frac{x-60}{60-y}\)=3/1
x+3y=240...(1)
x=240-3y=3(80-y)
We have 2 constraints
1. x=<100
2. x>y
Also, x will be a multiple of 3
x can be 99,96.....63
At x=60, y=60....Hence x can't take value equal to 60 or lower than 60.
Total number of integer values x can take= [\(\frac{99-63}{3}\)]+1=13
DisciplinedPrep
1 unit of x% alcohol is mixed with 3 units of y% alcohol to give 60% alcohol. If x > y, how many integer values can x take?
A. 10
B. 20
C. 35
D. 13
E. 30
A. 10
B. 20
C. 35
D. 13
E. 30
I don't get it. x and y are concentration in percent. 3 and 1 are the value of units.
the 2 equations will be
1x + 3y = ?
x+y=60.
So we have to find to the value of x for which it is greater than y and the first equation gives a valid number.
right?
