3L of milk are drawn from a container containing 30L of milk. It is re

Solution:

• Initial amount of milk in container = 30 L
• Initial amount of water in container = 0 L
• 3 L of milk is removed and replaced with water

o Amount of milk in container = 30 – 3 = 27L
o Amount of water in the container = 3L

 Ratio of milk to water = \(\frac{27}{3} = \frac{9}{1}\)
• Now, again 3L solution is removed from the container.

o In this case only milk is not removed, water is also removed.
o Milk removed from the container = \(\frac{9}{10}*3 = 2.7\) L

 Milk left in the container = \(27 – 2.7 = 24.3\) L
o Water removed from the container = \(\frac{1}{10}*3 = 0.3\)

 Water left in the container = \(3 – 0.3 = 2.7\) L
 Water in the container after the addition of 3 litre water = \(2.7+3 = 5.7\) L
o Ratio of milk to water = \(\frac{24.3}{5.7}\).
• Now, 3L solution is replaced with water one more time

o Milk removed = \(\frac{24.3}{30}*3 = 2.43\)

 Milk left in the solution = \(24.3 – 2.43 = 21.87\) L
o Water removed =\(\frac{5.7}{30}*3=0.57L\)

 Water left = \(5.7 – 0.57 = 5.13\) L
Water in container after the addition = \(5.13+3=8.13\)
• Ratio of milk to water = \(\frac{21.87}{8.13} = \frac{2187}{813}=\frac{729}{271}\)