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A baseball team won 45 percent of the first 80 games it played. How ma

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Bunuel
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A baseball team won 45 percent of the first 80 games it played. How ma [#permalink] New post   20 Dec 2015, 06:11
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A baseball team won 45 percent of the first 80 games it played. How many of the remaining 82 games will the team have to win in order to have won exactly 50 percent of all the games it played?

A. 36
B. 45
C. 50
D. 55
E. 81
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B
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Re: A baseball team won 45 percent of the first 80 games it played. How ma [#permalink] New post   20 Dec 2015, 06:15
Number of games won by baseball team in first 80 games = .45* 80 = 36
Total number of games = 80 + 82 = 162
% of wins required in 162 = 50
Number of wins required in 162 = 81

Number of wins required in remaining 82 games = 81 - 36 = 45

Answer B
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Re: A baseball team won 45 percent of the first 80 games it played. How ma [#permalink] New post   22 Dec 2015, 01:31
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Bunuel wrote:
A baseball team won 45 percent of the first 80 games it played. How many of the remaining 82 games will the team have to win in order to have won exactly 50 percent of all the games it played?

A. 36
B. 45
C. 50
D. 55
E. 81


Games won out of first 80 questions = (45/100)*80 = 36

Total Games = 80+82 = 162

Games to be won = (50/100)*162 = 81
Remaining games to be won = 81-36 = 45

Answer: Option B
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Re: A baseball team won 45 percent of the first 80 games it played. How ma [#permalink] New post   22 Dec 2015, 04:06
No. of games won in first 80 is 36
50% of the total games is 81...
More to be won is 81-36=45

Ans:B
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Re: A baseball team won 45 percent of the first 80 games it played. How ma [#permalink] New post   21 Jun 2017, 05:45
Bunuel wrote:
A baseball team won 45 percent of the first 80 games it played. How many of the remaining 82 games will the team have to win in order to have won exactly 50 percent of all the games it played?

A. 36
B. 45
C. 50
D. 55
E. 81


80(.45) =36

x/80 +82 = .5

81/162= .5

81-36 = 45

Thus
"B"
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Re: A baseball team won 45 percent of the first 80 games it played. How ma [#permalink] New post   21 Jun 2017, 07:02
Bunuel wrote:
A baseball team won 45 percent of the first 80 games it played. How many of the remaining 82 games will the team have to win in order to have won exactly 50 percent of all the games it played?

A. 36
B. 45
C. 50
D. 55
E. 81


Total games won till now is \(\frac{45}{100}*80 = 36\)

Total games required to play is \(82 + 80 = 162\)

Total wins required to have 50% win is \(81\)

Total wins required of the remaining games is \(81 - 36 = 45\)

Thus, answer will be (B) 45
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Re: A baseball team won 45 percent of the first 80 games it played. How ma [#permalink] New post   24 Jun 2017, 08:20
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Bunuel wrote:
A baseball team won 45 percent of the first 80 games it played. How many of the remaining 82 games will the team have to win in order to have won exactly 50 percent of all the games it played?

A. 36
B. 45
C. 50
D. 55
E. 81


The team won 0.45 x 80 = 36 of its first 80 games. We need to determine how many games must be won in the remaining 82 games such that the team would win 50% of its games. We can let n = the number of games needed to be won.

(36 + n)/162 = 1/2

2(36 + n) = 162

36 + n = 81

n = 45

Answer: B
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Re: A baseball team won 45 percent of the first 80 games it played. How ma [#permalink] New post   05 Nov 2023, 19:36
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Re: A baseball team won 45 percent of the first 80 games it played. How ma [#permalink]
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