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A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
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ShankSouljaBoi wrote:
Hi chetan2u ,

Can you please help with this one ?


Regards
:)



A line segment is drawn in the xy-coordinate plane with endpoints P(3,5) and Q(8,0). Line n is drawn so that it intersects PQ. What is the slope of line n?

So we have a clear line PQ, and another one n but nothing about that line..We require two points on n to get to our answer

(1) Point A is located on line n, and AP=AQ
We know from this that if we draw a perpendicular bisector of PQ, A can be anywhere on that line.
Nothing about the second point, so insuff.
If the second point is also equidistant from P and Q, then slope of n is same as that of the perpendicular of PQ. But if the second point is not on this line, there can be various possibilities of n as A is NOT fixed

(2) The x-intercept of line n is (3,0)
Nothing about second point.

Combined.
(3,0) is 5 away from P and 5 away from Q, so this point is also equidistant from P qnd Q.
If A is B, that is (3,0), then answer is that we cannot determine the slope as we do not have second point.
If A is something other than B, that is (3,0), then line n will have same slope as BA" or BA' which is same as perpendicular to PQ, so we can determine the slope.
Insuff

E
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A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
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slope of given line is ; 3-8/5-0 ; -1
#1
Point A is located on line n, and AP=AQ
the slope of line will be 1 as it does intersect at 90*
sufficient
#2
The x-intercept of line n is (3,0)
again many possiblities of having lines which can intersect line PQ insufficient
insufficient
IMO A


A line segment is drawn in the xy-coordinate plane with endpoints P(3,5) and Q(8,0). Line n is drawn so that it intersects PQ. What is the slope of line n?

(1) Point A is located on line n, and AP=AQ

(2) The x-intercept of line n is (3,0)

Originally posted by Archit3110 on 29 Nov 2019, 03:59.
Last edited by Archit3110 on 30 Nov 2019, 00:51, edited 2 times in total.
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Re: A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
I think explanation for statement- 2 needs review.
slope of n= 1 is conclusion of statement 1. slope(n) =1 is not mentioned in question stem.

For statement-1
A is on the perpendicular bisector of PQ.
Slope (PQ)= -1
then Slope (n)= 1
A is sufficient.

Statement-2
c= -3m
We don't know about c.
B is insufficient.

Archit3110 wrote:
slope of given line is ; 3-8/5-0 ; -1
#1
Point A is located on line n, and AP=AQ
the slope of line n must be 1 ; given point AP =AQ
so using distance formula we can determine point A ; sufficient
#2
we know the slope of line n = 1
y=mx+c
0=3+c
c=-3
eqn of line can be determined and slope m=1
sufficient
IMO D


A line segment is drawn in the xy-coordinate plane with endpoints P(3,5) and Q(8,0). Line n is drawn so that it intersects PQ. What is the slope of line n?

(1) Point A is located on line n, and AP=AQ

(2) The x-intercept of line n is (3,0)
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A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
...
A could be on line PQ so slope zero or P could be on perpendicular bisector. Hence we can find it whatever it be.
Insuff

B

No direction no slope . Only one point cannot dictate the equation of line n
Insuff

C--- Eliminates the possibility of A on PQ. HENCE, C



Posted from my mobile device

Originally posted by ShankSouljaBoi on 29 Nov 2019, 05:09.
Last edited by ShankSouljaBoi on 08 Jan 2020, 02:49, edited 1 time in total.
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Re: A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
(1) Point A is located on line n, and AP=AQ......... let (x,y) be the equidistant point from p,q...... Using distance formula for AP=AQ
(x-3)^2+(y-5)^2=(x-8)^2+y^2
x-y=3
The points which satisfies this equation....will be equidistant from p,q....this is the equation that intersects pq
Slope is 1
Sufficient

(2) The x-intercept of line n is (3,0)....... clearly insufficient....since with this we cannot find slope

OA:A

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A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
Slope of PQ = (0-5)/(8-3) = -5/5 = -1

(1) Point A is located on line n, and AP=AQ
Even though the point is equidistant from P and Q, it need not lie on the perpendicular bisector of PQ. So, slope is not fixed —>Insufficient


(2) The x-intercept of line n is (3,0)
We need to know at least 2 points on the line to find the slope —> Insufficient

Combining (1) & (2),
Note that (3,0) is equidistant from P and Q.
Also, point A is equidistant from P and Q.
So, the line passes through 2 points who are equidistant from end points of a line segment. Hence the line n is perpendicular bisector of PQ.

So, Slope of n*slope of PQ = -1
—> Slope of n*(-1) = -1
—> Slope of n = 1 —> Sufficient

IMO Option C

Posted from my mobile device

Originally posted by CareerGeek on 29 Nov 2019, 18:40.
Last edited by CareerGeek on 30 Nov 2019, 18:37, edited 1 time in total.
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Re: A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
Bunuel
Please post the solution..
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A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
Hi chetan2u ,

Can you please help with this one ?


Regards
:)
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A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
lnm87 wrote:
Bunuel wrote:
[header3 [/header3]

A line segment is drawn in the xy-coordinate plane with endpoints P(3,5) and Q(8,0). Line n is drawn so that it intersects PQ. What is the slope of line n?

(1) Point A is located on line n, and AP=AQ

(2) The x-intercept of line n is (3,0)




Easiest way to solve is to use graphical method(visualize).
Refer snapshot.
Attachment:
Linesegment PQ.JPG

Statement 1: Red line is 'line n'. Dotted red lines are various cases possible in statement. Even though we have a number of cases we see that slope of line n remains same which is perpendicular to line segment PQ. And since we can calculate slope of PQ(-ve here), we can get slope of line n.
(\(Slope of PQ = \frac{rise}{run} = \frac{0-5}{8-3} = -1\); Grid height and width differ a little hence perpendicularity is affected, If you make it on grid-pad it would be clear)

SUFFICIENT.

Statement 2: Dotted Green lines indicate various possibilities of line n that have x-intercept of line n at (3,0).

INSUFFICIENT.

Answer A.



The points where the green lines intersect the red line are all points A with AQ=AP, there are two different lines with different slopes ERGO (1) insufficent
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Re: A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
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Re: A line segment is drawn in the xy-coordinate plane with endpoints P(3, [#permalink]
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