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Re: A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
I was thinking about how to do it fast.

We simply have to look at the options.

According to the second expression, the sum of x and y should be multiplied on at least 4.

C, D and E give us a result that is more than 28k. As a result, the only two options are A and B. We choose the B because we are looking for Max.

Posted from my mobile device
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Re: A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
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Since we have to produce both balls and boxes to a maximum capacity, we can't neglect any of the terms.

Constraint 1:

we need to have a value such that 7x+6y<=38.
2 Possible situations are 7*1 + 6*5 <=38 or 7*4+6*1 <= 38
So, according to this equation, we can produce 6000 (1000+5000) or 5000 (4000+1000)

Constraint 2
Similarly, we have 2 possibilities to get close to 28.
4*2+5*4 <= 28 or 4*5+5*1 <= 28
According to this equation, we can produce 6000 (2000+4000) or 6000 (5000+1000)

Combining both the constraints, the maximum we can produce is 6000. Answer is B
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Re: A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
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parkhydel wrote:
\(7x + 6y \leq 38,000\)

\(4x + 5y \leq 28,000\)

A manufacturer wants to produce x balls and y boxes. Resource constraints require that x and y satisfy the inequalities shown. What is the maximum number of balls and boxes combined that can be produced given the resource constraints?

A.  5,000
B.  6,000
C.  7,000
D.  8,000
E. 10,000

PS30421.02


\(7x + 6y \leq 38,000\)---------------->(I)
\(4x + 5y \leq 28,000\)---------------->(II)

(I) + (II) => \(11x + 11y \leq 66000\) Or, \(x + y \leq 6000\), Answer must be (B)
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Re: A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
I solved this question by solving for two simultaneous equations - apart form taking too long, any other potential issues with this approach?

EMPOWERgmatRichC, would appreciate your input on how to solve a question like this as fast as possible :)
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Re: A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
Adding the two INEQUALITIES together:
11x + 11y <= 66000
x + y <= 6000


Answer: B
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Re: A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
If we subtract the two equations, we get 3x + y <= 10,000
After further solving we get x = 1000 and Y = 7000

The total combined Value of balls and boxes would be 8000.
Could someone shed a light on where did I go wrong?
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Re: A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
chetan2u wrote:
parkhydel wrote:
\(7x + 6y \leq 38,00\)

\(4x + 5y \leq 28,00\)

A manufacturer wants to produce x balls and y boxes. Resource constraints require that x and y satisfy the inequalities shown. What is the maximum number of balls and boxes combined that can be produced given the resource constraints?

A.  5,000
B.  6,000
C.  7,000
D.  8,000
E. 10,000

PS30421.02



I believe the equations must be talking of 28,000 and 38000 and not 3800 and 2800 because we have a comma after sets of 3 digit in GMAT, and also answers are in 1000s.

\(7x + 6y \leq 38,000\)

\(4x + 5y \leq 28,000\)

Add both the inequalities..
\(7x+6y+4x=5y\leq{38000+28000}\)

\(11x+11y\leq{66000}....x+y\leq{6000}\)

B

Hello,
If x+y is lesser than or equal to 6000, why couldn't the answer be A)5000? How did you eliminate it?
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Re: A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
Expert Reply
ksramanv wrote:
chetan2u wrote:
parkhydel wrote:
\(7x + 6y \leq 38,00\)

\(4x + 5y \leq 28,00\)

A manufacturer wants to produce x balls and y boxes. Resource constraints require that x and y satisfy the inequalities shown. What is the maximum number of balls and boxes combined that can be produced given the resource constraints?

A.  5,000
B.  6,000
C.  7,000
D.  8,000
E. 10,000

PS30421.02



I believe the equations must be talking of 28,000 and 38000 and not 3800 and 2800 because we have a comma after sets of 3 digit in GMAT, and also answers are in 1000s.

\(7x + 6y \leq 38,000\)

\(4x + 5y \leq 28,000\)

Add both the inequalities..
\(7x+6y+4x=5y\leq{38000+28000}\)

\(11x+11y\leq{66000}....x+y\leq{6000}\)

B

Hello,
If x+y is lesser than or equal to 6000, why couldn't the answer be A)5000? How did you eliminate it?


We are looking at the MAXIMUM number, and 6000 is the maximum value of x+y.
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A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
We can add inequalities if the inequality sign faces the same way.
Therefore add equations 1 & 2
11x+11y</= 66000
x+y</= 6000(ans)
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Re: A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
parkhydel wrote:
\(7x + 6y \leq 38,000\)

\(4x + 5y \leq 28,000\)

A manufacturer wants to produce x balls and y boxes. Resource constraints require that x and y satisfy the inequalities shown. What is the maximum number of balls and boxes combined that can be produced given the resource constraints?

A.  5,000
B.  6,000
C.  7,000
D.  8,000
E. 10,000

PS30421.02


We can add the inequalities as their signs are in the same direction. So, adding both we get:

\(7x + 6y \leq 38,000\)
\(4x + 5y \leq 28,000\)

\(11x + 11y \leq 66000\)

Then, divide the equation by 11

\(x + y \leq 6,000\)

So, correct answer is 6000
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Re: A manufacturer wants to produce x balls and y boxes. Resource constrai [#permalink]
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