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Difficulty:
95%
(hard)
Question Stats:
14% (01:34) correct
86%
(01:39)
wrong
based on 102
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A show has four answer choices for each question - A, B, C, and D. The participant, John, correctly knows that the right answer is either A or D. The show has a '50:50' option by using which participants can eliminate two wrong answer choices. What is the probability that John uses the '50:50' option and is still left with both A and D?
A. 1/2
B. 1/3
C. 1/4
D. 1/5
E. 1/ 6
A. 1/2
B. 1/3
C. 1/4
D. 1/5
E. 1/ 6
24 Jun 2021, 05:23
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Abhibarua
A reality show has four answer choices for each question - A, B, C, and D. The participant, John, correctly knows that the right answer is between A and D. The show has a '50:50' option by using which participants can eliminate two wrong answer choices. What is the probability that John uses the '50:50' option and is still left with answer choices A and D?
A. 1/4
B. 1/5
C. 1/6
D. 1/10
E. 1/ 12
A. 1/4
B. 1/5
C. 1/6
D. 1/10
E. 1/ 12
This is a good question concept, but there are several problems with the question as written. Most importantly, the right answer isn't among the choices. When the game show eliminates two answers, it must eliminate two of the three wrong answers. So it must leave one of the three wrong answers 'on the board'. So there's a 1/3 chance they'll leave up the wrong answer John is worried about, and a 2/3 chance they'll leave up one of the other two wrong answers, and the answer is 1/3. If that's a bit conceptual, you can imagine that the right answer is actually A. Then the game show is obligated to leave exactly one of B, C or D on the board, so there's a 1/3 chance they leave D up. The same is true when the right answer is D; then there is a 1/3 chance they leave A up. So no matter what answer is right, there's a 1/3 chance A and D are still available after the 50-50 is used.
But I think the question means to describe a "game show" (not a "reality show") and they really shouldn't say "between A and D" after listing the options in order. If we say "x is an integer between 1 and 4", we mean "x is either 2 or 3". We do not mean "x is one of the two numbers 1 or 4", but that is (I assume) the intended meaning in this question. What is the source?
25 Jul 2021, 04:55
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IanStewart
Abhibarua
A reality show has four answer choices for each question - A, B, C, and D. The participant, John, correctly knows that the right answer is between A and D. The show has a '50:50' option by using which participants can eliminate two wrong answer choices. What is the probability that John uses the '50:50' option and is still left with answer choices A and D?
A. 1/4
B. 1/5
C. 1/6
D. 1/10
E. 1/ 12
A. 1/4
B. 1/5
C. 1/6
D. 1/10
E. 1/ 12
This is a good question concept, but there are several problems with the question as written. Most importantly, the right answer isn't among the choices. When the game show eliminates two answers, it must eliminate two of the three wrong answers. So it must leave one of the three wrong answers 'on the board'. So there's a 1/3 chance they'll leave up the wrong answer John is worried about, and a 2/3 chance they'll leave up one of the other two wrong answers, and the answer is 1/3. If that's a bit conceptual, you can imagine that the right answer is actually A. Then the game show is obligated to leave exactly one of B, C or D on the board, so there's a 1/3 chance they leave D up. The same is true when the right answer is D; then there is a 1/3 chance they leave A up. So no matter what answer is right, there's a 1/3 chance A and D are still available after the 50-50 is used.
But I think the question means to describe a "game show" (not a "reality show") and they really shouldn't say "between A and D" after listing the options in order. If we say "x is an integer between 1 and 4", we mean "x is either 2 or 3". We do not mean "x is one of the two numbers 1 or 4", but that is (I assume) the intended meaning in this question. What is the source?
Thanks for your feedback. I edited the question for better clarity.
