A student cuts 80 rectangles from construction paper, all of which are at least 10 inches in length and in width, and 20 percent of rectangles that are greater than 10 inches long are exactly 10 inches wide. if 40 of the rectangles have a length of exactly 10 inches and 50 of the rectangles are greater than 10 inches wide. How many rectangles have a perimeter of greater than 40 inches? (Note: assume that width and length are interchangeable; in other words, width does not have to be shorter than length)

(A) 18
(B) 22
(C) 32
(D) 58
(E) 66

Dear Vyshak, Request you to explain as to how you arrived at the break up of 22 / 8 / 18 and 32. I understood rest of the figures and calculation.

Length and width are atleast 10 inches.
Total number of rectangles = 80

Number of rectangles with length of 10 inches = 40 --> Number of rectangles with length greater than 10 inches = 40
Number of rectangles with width greater than 10 inches = 50 --> Number of rectangles with width of 10 inches = 30

20 percent of rectangles that are greater than 10 inches long are exactly 10 inches wide --> (1/5)*40 = 8 rectangles with l > 10 and w = 10.

You will be able to find the other blank cells once you know the above values.