NEW HERE? LEARN MORE
closeclose
Last visit was: 25 Apr 2024, 22:06 It is currently 25 Apr 2024, 22:06
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

According to the formula F = 9/5*C + 32, if the temperature in degrees

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
B
usre123
Manager
Manager
Joined: 30 Mar 2013
Posts: 80
Own Kudos [?]: 180 [77]
Given Kudos: 197
Location: United States
Schools: Alberta '23 (WL)
GMAT 1: 760 Q50 V44
Send PM
GMAT ToolKit User
According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   Updated on: 04 Feb 2019, 04:49
6
Kudos
71
Bookmarks
00:00
A
B
C
D
E

Difficulty:

35% (medium)

Question Stats:

75% (02:09) correct 25% (02:25) wrong based on 1113 sessions
Hide Show timer Statistics
According to the formula \(F=\frac{9}{5}*C +32\), if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?


(A) 9

(B) 15

(C) 47

(D) \(48 \frac{3}{5}\)

(E) 59
ShowHide Answer
Official Answer
B

Originally posted by usre123 on 27 Sep 2013, 23:25.
Last edited by Bunuel on 04 Feb 2019, 04:49, edited 2 times in total.
Renamed the topic and edited the question.
Most Helpful Reply
User avatar
L
KarishmaB
Tutor
Joined: 16 Oct 2010
Posts: 14823
Own Kudos [?]: 64925 [21]
Given Kudos: 426
Location: Pune, India
Send PM
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   03 Jan 2017, 04:49
15
Kudos
6
Bookmarks
Expert Reply
skimmingit wrote:
Could someone please explain what happens to the F=9/5 (C) +32? In all of the provided solutions, no one does anything with this, but I'm confused as to why that is.



32 is constant. It doesn't bring about the change. The change is defined by the relation between F and C only. 32 just gets cancelled out.

F1 = (9/5)*C1 + 32 ......(I)
F2 = (9/5)*C2 + 32 ......(II)

(II) - (I)

F2 - F1 = (9/5)*(C2 - C1) + 32 - 32

F2 - F1 = (9/5)*(C2 - C1)

27 = (9/5)*(C2 - C1)

(C2 - C1) = 15
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619057 [12]
Given Kudos: 81595
Send PM
CAT Tests Forum Quiz Mode
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   28 Sep 2013, 04:09
7
Kudos
5
Bookmarks
Expert Reply
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59


You can plug in values.

C = 5/9*(F-32)

F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.

Increase = 15 degrees.

Answer: B.
General Discussion
User avatar
B
mau5
Verbal Forum Moderator
Joined: 10 Oct 2012
Posts: 485
Own Kudos [?]: 3093 [7]
Given Kudos: 141
Send PM
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   27 Sep 2013, 23:52
3
Kudos
4
Bookmarks
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59


\(F_i = \frac{9}{5}* (C_i) +32\)

\(F_i+27= \frac{9}{5}* (C_f) +32\)

On Subtracting, we get\(27 = \frac{9}{5}* (C_f-C_i) \to (C_f-C_i) = 3*5 = 15\)

B.
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619057 [4]
Given Kudos: 81595
Send PM
CAT Tests Forum Quiz Mode
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   02 Oct 2013, 03:35
2
Kudos
2
Bookmarks
Expert Reply
usre123 wrote:
Bunuel wrote:
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59


You can plug in values.

C = 5/9*(F-32)

F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.

Increase = 15 degrees.

Answer: B.


I dont understand why you only multiplied 5/9 by 27. what about F-32?


If F=59, then \(C = \frac{5}{9}*(F-32) = \frac{5}{9}*(59-32) = \frac{5}{9}*27 = 15\).

Does this make sense?
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619057 [2]
Given Kudos: 81595
Send PM
CAT Tests Forum Quiz Mode
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   28 Sep 2013, 04:11
1
Kudos
1
Bookmarks
Expert Reply
Bunuel wrote:
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59


You can plug in values.

C = 5/9*(F-32)

F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.

Increase = 15 degrees.

Answer: B.


Other conversion problems to practice:
if-an-object-travels-100-feet-in-2-seconds-what-is-the-103364.html
the-rear-wheels-of-a-car-crossed-a-certain-line-0-5-second-135753.html
a-train-traveling-at-a-constant-speed-down-a-straight-track-87124.html
a-welder-received-an-order-to-make-a-1-million-liter-126154.html
a-car-traveling-at-a-certain-constant-speed-takes-2-seconds-126658.html
if-an-automobile-averaged-22-5-miles-per-gallon-of-gasoline-109083.html
if-1-kilometer-is-approximately-0-6-mile-which-of-the-140731.html
measuring-standards-conversion-106516.html
if-10-millimeters-equal-1-centimeter-how-many-square-48538.html
the-speed-of-light-is-approximately-149492.html
the-rear-wheels-of-a-car-crossed-a-certain-line-0-5-second-135753.html
if-the-speed-of-x-meters-per-second-is-equivalent-to-the-127005.html

Hope this helps.
User avatar
L
MathRevolution
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 10161
Own Kudos [?]: 16598 [2]
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Send PM
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   24 Dec 2020, 00:17
1
Kudos
1
Bookmarks
Expert Reply
Given expression is in terms of F but we need the value of C, hence we will express the expression in terms of C.

F = \(\frac{9}{5}\) * C + 32

At C = 0, F = 32

Increased value: F = 32 + 27 = 59

=> C = \(\frac{5}{9}\) * ( F - 32)

=> C = \(\frac{5}{9}\) * ( 59 - 32)

=> C = \(\frac{5}{9}\) * 27

=> C = 15

Answer B
User avatar
G
testcracker
Manager
Manager
Joined: 24 Mar 2015
Status:love the club...
Posts: 220
Own Kudos [?]: 112 [1]
Given Kudos: 527
Send PM
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   19 Aug 2017, 13:26
1
Kudos
VeritasPrepKarishma wrote:
skimmingit wrote:
Could someone please explain what happens to the F=9/5 (C) +32? In all of the provided solutions, no one does anything with this, but I'm confused as to why that is.



32 is constant. It doesn't bring about the change. The change is defined by the relation between F and C only. 32 just gets cancelled out.

F1 = (9/5)*C1 + 32 ......(I)
F2 = (9/5)*C2 + 32 ......(II)

(II) - (I)

F2 - F1 = (9/5)*(C2 - C1) + 32 - 32

F2 - F1 = (9/5)*(C2 - C1)

27 = (9/5)*(C2 - C1)

(C2 - C1) = 15


hi mam

since the change is defined by the relation between F and C only, we can say directly that the "change in F" is equal to 9/5 times the "change in C". That's it...

thanks mam .. :thumbup:
User avatar
B
usre123
Manager
Manager
Joined: 30 Mar 2013
Posts: 80
Own Kudos [?]: 180 [0]
Given Kudos: 197
Location: United States
Schools: Alberta '23 (WL)
GMAT 1: 760 Q50 V44
Send PM
GMAT ToolKit User
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   01 Oct 2013, 10:54
Bunuel wrote:
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59


You can plug in values.

C = 5/9*(F-32)

F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.

Increase = 15 degrees.

Answer: B.


I dont understand why you only multiplied 5/9 by 27. what about F-32?
avatar
skimmingit
Intern
Intern
Joined: 11 Jul 2016
Posts: 1
Own Kudos [?]: [0]
Given Kudos: 6
Send PM
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   02 Jan 2017, 14:37
Could someone please explain what happens to the F=9/5 (C) +32? In all of the provided solutions, no one does anything with this, but I'm confused as to why that is.
User avatar
bumpbot
Non-Human User
Joined: 09 Sep 2013
Posts: 32681
Own Kudos [?]: 822 [0]
Given Kudos: 0
Send PM
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink] New post   10 Jul 2023, 22:27
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
gmatclubot
Re: According to the formula F = 9/5*C + 32, if the temperature in degrees [#permalink]
10 Jul 2023, 22:27
Moderators:
Bunuel
Math Expert
92915 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions