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Updated on: 14 Jul 2012, 03:00
Originally posted by barakhaiev on 20 Nov 2009, 05:14.
Last edited by Bunuel on 14 Jul 2012, 03:00, edited 1 time in total.
Last edited by Bunuel on 14 Jul 2012, 03:00, edited 1 time in total.
Edited the question and added the OA.
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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A train traveling at a constant speed down a straight track crosses a certain line on the track. If the rear wheels of the train cross the line 2 seconds after the front wheels, and the centers of the rear and front wheels are 100 feet apart, which of the following expresses the speed of the train in miles per hour?
1 mile = 5280 feet
(A) \((100/5280)(60^2/2)\)
(B) \((100/5280)(60/2)\)
(C) \((100/5280)(2/60^2)\)
(D) \((100/60^2)(5280/2)\)
(E) \((100/60)(5280/2)\)
1 mile = 5280 feet
(A) \((100/5280)(60^2/2)\)
(B) \((100/5280)(60/2)\)
(C) \((100/5280)(2/60^2)\)
(D) \((100/60^2)(5280/2)\)
(E) \((100/60)(5280/2)\)
20 Nov 2009, 05:32
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barakhaiev
Speed of the train would be 100/2 feet per second, as it covers the distance of 100 feet in 2 seconds.
We should transform this to miles per hour:
100 feet=100/5280 miles;
2 seconds=2/60^2 hours;
Hence we would have (100/5280)/(2/60^2)=(100/5280)*(60^2/2) miles per hour.
Answer: A.
General Discussion
20 Nov 2009, 12:26
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agree. 50 feet per second * 60 (convert to minutes) * 60 (convert to hours) this gives you feet per hour. Divide by 5260 = Miles per hour
