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B
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Difficulty:
35%
(medium)
Question Stats:
75% (02:09) correct
25%
(02:25)
wrong
based on 1244
sessions
History
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According to the formula \(F=\frac{9}{5}*C +32\), if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?
(A) 9
(B) 15
(C) 47
(D) \(48 \frac{3}{5}\)
(E) 59
(A) 9
(B) 15
(C) 47
(D) \(48 \frac{3}{5}\)
(E) 59
03 Jan 2017, 04:49
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skimmingit
Could someone please explain what happens to the F=9/5 (C) +32? In all of the provided solutions, no one does anything with this, but I'm confused as to why that is.
32 is constant. It doesn't bring about the change. The change is defined by the relation between F and C only. 32 just gets cancelled out.
F1 = (9/5)*C1 + 32 ......(I)
F2 = (9/5)*C2 + 32 ......(II)
(II) - (I)
F2 - F1 = (9/5)*(C2 - C1) + 32 - 32
F2 - F1 = (9/5)*(C2 - C1)
27 = (9/5)*(C2 - C1)
(C2 - C1) = 15
28 Sep 2013, 04:09
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usre123
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?
A)9
B)15
C)47
D) 48 3/5
E) 59
A)9
B)15
C)47
D) 48 3/5
E) 59
You can plug in values.
C = 5/9*(F-32)
F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.
Increase = 15 degrees.
Answer: B.
