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Re: An international rugby team composed of four people must be organized [#permalink]
Let the Iranian players \(= I\), and the Turkish players \(= T\). Analyzing the question, we see that there is a constraint given where each selection of a team of four players must have at least two Iranian players. Therefore, there are three cases that we need to consider to solve this problem, namely:

Case 1: Two Iranian players and two Turkish players, i.e. \(IITT\), or \(6C2*5C2=150\)
OR
Case 2: Three Iranian players and one Turkish player, i.e. \(IIIT\), or \(6C3*5C1=100\)
OR
Case 3: Four Iranian players and no Turkish players, i.e. \(IIII\), or \(6C4=15\)

Either of these three cases can be true, so we can add them up to get \(150+100+15=265\). Option (B) is the correct answer.

Hope this helps!

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Re: An international rugby team composed of four people must be organized [#permalink]
Another approach to answer this could be the reverse way of thinking.
The question asks for total number of combinations possible when at least 2 players are Iranian. There are two approaches to solve this problem.

Straight forward way
Here we calculate the possible combinations of these independent events, and eventually add them, since keyword "or" is involved (i.e. mutually exclusive)
2 Iranian and 2 Turkish = 6C2 * 5C2 = (3*5) * (5*2) = 15*10 = 150
3 Iranian and 1 Turkish = 6C3 * 5C1 = (5*4) * 5 = 20*5 = 100
4 Iranian and 0 Turkish = 6C4 * 5C0 = (5*3) * 1 = 15

Now we add them all up all the likely scenarios for solution => 150 + 100 + 15 = 265

Alternate Approach
Here we calculate all the possible combinations and deduct all the combinations which cannot happen.
Total number of combinations = 11C4 = 330
0 Iranian and 4 Turkish = 6C0 * 5C4 = 1*5 = 5
1 Iranian and 3 Turkish = 6C1 * 5C3 = 6*10 = 60

Total number of selection possible - Not getting what we want => 330 - (5+60) = 265
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Re: An international rugby team composed of four people must be organized [#permalink]
GMATinsight wrote:
Orvil wrote:
An international rugby team composed of 4 people must be organized from among 5 Turkish players and 6 Iranian players. If a team must have at least 2 Iranian players, how many different ways are there to produce the team?

The official answer is 265.

I solved the problem in the following way:
Selecting 2 players from 6 iranian players: 6C2 + Selecting the rest of the players: 9C2 (9 players remain after selecting the first two.

Can anyone help me with what's wrong with my method? The problem has been posted here before but the thread is not accessible. Any help will be appreciated.



Your calculation is flawed as there are some repeated cases
e.g Iranians {ABCDEF} and Turkish {PQRST}

Case 1: 2 iranian selected are {AB}, now, 9C2 might select {CQ}
Case 2: 2 iranian selected are {AC}, now, 9C2 might select {BQ}
Now, you can understadn that these two cases are identical but the calculation has counted it two times hence the REPETITION


You must make separate cases in this question as follows

5 Turkish players and 6 Iranian players, team must have at least 2 Iranian players
Case 1: 2 Iranians and 2 Turkish : 6C2*5C2 = 15*10 = 150
Case 2: 3 Iranians and 1 Turkish : 6C3*5C1 = 20*5 = 100
Case 3: 4 Iranians and 0 Turkish : 6C4*5C0 = 15*1 = 15

Total Outcomes = 150+100+15 = 265

Orvil

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Hi,

I created similar cases like above. However, I didn't use the selection formula and use the basic counting principle to fill in the spots and got a different answer.

Case 1: 2 Iranians and 2 Turkish : 6* 5* 5T*4T = 600
Case 2: 3 Iranians and 1 Turkish : 6*5*4* 5T = 600
Case 3: 4 Iranians and 0 Turkish : 6*5*4*3 = 240


Can you help me understand the flaw in reasoning? Any resources/links to fill in this gap would be really helpful too.

chetan2u Bunuel KarishmaB
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Re: An international rugby team composed of four people must be organized [#permalink]
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prakashb2497 wrote:
GMATinsight wrote:
Orvil wrote:
An international rugby team composed of 4 people must be organized from among 5 Turkish players and 6 Iranian players. If a team must have at least 2 Iranian players, how many different ways are there to produce the team?

The official answer is 265.

I solved the problem in the following way:
Selecting 2 players from 6 iranian players: 6C2 + Selecting the rest of the players: 9C2 (9 players remain after selecting the first two.

Can anyone help me with what's wrong with my method? The problem has been posted here before but the thread is not accessible. Any help will be appreciated.



Your calculation is flawed as there are some repeated cases
e.g Iranians {ABCDEF} and Turkish {PQRST}

Case 1: 2 iranian selected are {AB}, now, 9C2 might select {CQ}
Case 2: 2 iranian selected are {AC}, now, 9C2 might select {BQ}
Now, you can understadn that these two cases are identical but the calculation has counted it two times hence the REPETITION


You must make separate cases in this question as follows

5 Turkish players and 6 Iranian players, team must have at least 2 Iranian players
Case 1: 2 Iranians and 2 Turkish : 6C2*5C2 = 15*10 = 150
Case 2: 3 Iranians and 1 Turkish : 6C3*5C1 = 20*5 = 100
Case 3: 4 Iranians and 0 Turkish : 6C4*5C0 = 15*1 = 15

Total Outcomes = 150+100+15 = 265

Orvil

CLICK HERE For Accessing many Videos on Combinatorics and SUBSCRIBE the channel


1st Video solutions based Modular On-Demand QUANT Course: All Concepts | 2000+Qns | 20+ Tests |
Two MUST join YouTube channels : GMATinsight (1000+ FREE Videos) and GMATclub :)



Hi,

I created similar cases like above. However, I didn't use the selection formula and use the basic counting principle to fill in the spots and got a different answer.

Case 1: 2 Iranians and 2 Turkish : 6* 5* 5T*4T = 600
Case 2: 3 Iranians and 1 Turkish : 6*5*4* 5T = 600
Case 3: 4 Iranians and 0 Turkish : 6*5*4*3 = 240


Can you help me understand the flaw in reasoning? Any resources/links to fill in this gap would be really helpful too.

chetan2u Bunuel KarishmaB


Basic Counting Principle is used when you are selecting from a single group and you need to arrange the selection too. Here we only need to select a group of 4 people from two groups - Iranians and Turkish. There is no arrangement involved. We cannot use the Basic Counting Principle here.
If the 4 needed to be arranged in 4 distinct spots on the team (such as Quarterback, centre, wings and fullback), then we would have arranged the 4 selected players.
GMAT Club Bot
Re: An international rugby team composed of four people must be organized [#permalink]
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