Orvil wrote:
An international rugby team composed of 4 people must be organized from among 5 Turkish players and 6 Iranian players. If a team must have at least 2 Iranian players, how many different ways are there to produce the team?
The official answer is 265.
I solved the problem in the following way:
Selecting 2 players from 6 iranian players: 6C2 + Selecting the rest of the players: 9C2 (9 players remain after selecting the first two.
Can anyone help me with what's wrong with my method? The problem has been posted here before but the thread is not accessible. Any help will be appreciated.
Your calculation is flawed as there are some repeated cases
e.g Iranians {ABCDEF} and Turkish {PQRST}
Case 1: 2 iranian selected are {AB}, now, 9C2 might select {CQ}
Case 2: 2 iranian selected are {AC}, now, 9C2 might select {BQ}
Now, you can understadn that these two cases are identical but the calculation has counted it two times hence the REPETITION
You must make separate cases in this question as follows
5 Turkish players and 6 Iranian players, team must have at least 2 Iranian players
Case 1: 2 Iranians and 2 Turkish : 6C2*5C2 = 15*10 = 150
Case 2: 3 Iranians and 1 Turkish : 6C3*5C1 = 20*5 = 100
Case 3: 4 Iranians and 0 Turkish : 6C4*5C0 = 15*1 = 15
Total Outcomes = 150+100+15 = 265
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