Oct 16 08:00 PM PDT  09:00 PM PDT EMPOWERgmat is giving away the complete Official GMAT Exam Pack collection worth $100 with the 3 Month Pack ($299) Oct 18 08:00 AM PDT  09:00 AM PDT Learn an intuitive, systematic approach that will maximize your success on Fillintheblank GMAT CR Questions. Oct 19 07:00 AM PDT  09:00 AM PDT Does GMAT RC seem like an uphill battle? eGMAT is conducting a free webinar to help you learn reading strategies that can enable you to solve 700+ level RC questions with at least 90% accuracy in less than 10 days. Sat., Oct 19th at 7 am PDT Oct 20 07:00 AM PDT  09:00 AM PDT Get personalized insights on how to achieve your Target Quant Score. Oct 22 08:00 PM PDT  09:00 PM PDT On Demand for $79. For a score of 4951 (from current actual score of 40+) AllInOne Standard & 700+ Level Questions (150 questions)
Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 09 Feb 2013
Posts: 111

At a local beach, the ratio of little dogs to average dogs
[#permalink]
Show Tags
13 Jun 2013, 23:35
Question Stats:
41% (03:18) correct 59% (03:12) wrong based on 296 sessions
HideShow timer Statistics
At a local beach, the ratio of little dogs to average dogs to enormous dogs is 2:5:8. Late in the afternoon, the ratio of little dogs to average dogs doubles and the ratio of little dogs to enormous dogs increases. If the new percentage of little dogs and the new percentage of average dogs are both integers and there are fewer than 30 total dogs at the beach, which of the following represents a possible new percentage of enormous dogs? A. 25% B. 40% C. 50% D. 55% E. 70%
Official Answer and Stats are available only to registered users. Register/ Login.
_________________
Kudos will encourage many others, like me. Good Questions also deserve few KUDOS.




Intern
Joined: 28 Jul 2013
Posts: 7

Re: At a local beach, the ratio of little dogs to average dogs
[#permalink]
Show Tags
03 Oct 2013, 06:23
emmak wrote: At a local beach, the ratio of little dogs to average dogs to enormous dogs is 2:5:8. Late in the afternoon, the ratio of little dogs to average dogs doubles and the ratio of little dogs to enormous dogs increases. If the new percentage of little dogs and the new percentage of average dogs are both integers and there are fewer than 30 total dogs at the beach, which of the following represents a possible new percentage of enormous dogs?
A. 25% B. 40% C. 50% D. 55% E. 70% This problem can be solved with a shortcut which the GMAT typically expects. If you consider the percentage of enormous dogs as x, then the percentage of the rest of the dogs becomes 100x. Now this percentage is split between the 2 types of dogs in the ratio of 4:5. We also know that the percentages have to be integers. Meaning 100x will have to be divisible by 9 A quick look at the solutions tells us that 100x is divisible by 9 only in the case if D.




Intern
Joined: 26 May 2010
Posts: 10

Re: At a local beach, the ratio of little dogs to average dogs
[#permalink]
Show Tags
Updated on: 14 Jun 2013, 00:21
emmak wrote: At a local beach, the ratio of little dogs to average dogs to enormous dogs is 2:5:8. Late in the afternoon, the ratio of little dogs to average dogs doubles and the ratio of little dogs to enormous dogs increases. If the new percentage of little dogs and the new percentage of average dogs are both integers and there are fewer than 30 total dogs at the beach, which of the following represents a possible new percentage of enormous dogs? A)25% B)40% C)50% D)55% E)70% Little Dogs(L), Average Dogs(A) and Enormous Dogs (E) The initial ratio for L:A:E :: 2:5:8 Initial Total dogs = 15X ( x assumed; 2+5+8= 15), Since the total dogs are less than 30 therefore initial total value has to be 15 L = 2, A = 5 E = 8 L:A= 2:5 This ratio doubles Hence New Dog count is L= 4 , A = 5 E= X: Also 4+5+x<30 We need to Find X*100/(4+5+X) Now it says that new percentage of little dogs and Average dogs is an integer %L = 4*100/(9+x) %A = 5*100/(9+x); Only Value for X is 11 ; 9+x<30 and % integer Therefore, Enormus Dogs % is = 11*100/(20) = 55% D is the Ans Kudos is the Karma
Originally posted by bhuwangupta on 14 Jun 2013, 00:17.
Last edited by bhuwangupta on 14 Jun 2013, 00:21, edited 1 time in total.



Verbal Forum Moderator
Joined: 10 Oct 2012
Posts: 590

Re: At a local beach, the ratio of little dogs to average dogs
[#permalink]
Show Tags
14 Jun 2013, 00:18
emmak wrote: At a local beach, the ratio of little dogs to average dogs to enormous dogs is 2:5:8. Late in the afternoon, the ratio of little dogs to average dogs doubles and the ratio of little dogs to enormous dogs increases. If the new percentage of little dogs and the new percentage of average dogs are both integers and there are fewer than 30 total dogs at the beach, which of the following represents a possible new percentage of enormous dogs? A)25% B)40% C)50% D)55% E)70% Given ratio of Little Dogs:Average Dogs = 2:5. When this ratio doubles, it becomes 4:5. Ratio between Little dogs: Enormous dogs = 2:8. Also, this increases from 2:8>1:4 to 4:(8+x) , where x is an nonnegative integer(Maximum value which x can assume is 7, under the given conditions) New % of little dogs =\(\frac{4}{(4+5+8+x)}*100\)= \(\frac{4}{(17+x)}*100\) The minimum value of x, for which this is an integer ; x = 3. Similarly, % of average dogs =\(\frac{5}{(17+x)}*100\). Again, x = 3 for an integral value. Thus, the new percentage of enormous dogs =\(\frac{(8+3)}{20}*100\)= 55 % D.
_________________



Manager
Joined: 29 Aug 2013
Posts: 69
Location: United States
Concentration: Finance, International Business
GMAT 1: 590 Q41 V29 GMAT 2: 540 Q44 V20
GPA: 3.5
WE: Programming (Computer Software)

Re: At a local beach, the ratio of little dogs to average dogs
[#permalink]
Show Tags
08 Oct 2013, 09:10
emmak wrote: At a local beach, the ratio of little dogs to average dogs to enormous dogs is 2:5:8. Late in the afternoon, the ratio of little dogs to average dogs doubles and the ratio of little dogs to enormous dogs increases. If the new percentage of little dogs and the new percentage of average dogs are both integers and there are fewer than 30 total dogs at the beach, which of the following represents a possible new percentage of enormous dogs?
A. 25% B. 40% C. 50% D. 55% E. 70% I like to go straight forward and with the question stem. This is how I solved analyzing the question sentence by sentence. 1) Initially the ratio of Local : Average : Enormous is 2:5:8. 2) After afternoon ratios become : 4:5:x (since we do not know in what ratio are enormous dogs in) 3) Initially Local : Enormous ratio is 1:4. Now, Ques stem says that this ratio increases. Therefore new ratio i.e. 4:x > 1:4 ; this gives us x < 16. 4) Now, percentage of Local dogs in afternoon is \(\frac{(4*100)}{(9+x)}\) and average dogs is \(\frac{(5*100)}{(9+x)}\) 5) These ratios will be integers only when the denominators of these terms are common factors of 400 and 500 and the multiplication of those factors such as 2,5,10,20,50 etc. Since x is less than 16, x can only be 1 and 11 so that the denominators are 10 and 20 respectively. 6) Therefore the possible percentages of Enormous dogs can be 10% (i.e. (1/(9+1))*100 considering x = 1) and 55% (i.e. (11/(9+11))*100 considering x = 11) Only 55% is in the options hence D Consider Kudos if the post helped!!



Senior Manager
Joined: 08 Apr 2012
Posts: 327

Re: At a local beach, the ratio of little dogs to average dogs
[#permalink]
Show Tags
31 Aug 2014, 11:08
bhuwangupta wrote: Now it says that new percentage of little dogs and Average dogs is an integer %L = 4*100/(9+x) %A = 5*100/(9+x); Only Value for X is 11 ; 9+x<30 and % integer Kudos is the Karma Why is this true? Why can't x=1? Am I missing something here?



Intern
Joined: 04 Nov 2018
Posts: 13
Concentration: Finance, General Management
GPA: 3.83
WE: Sales (Retail)

Re: At a local beach, the ratio of little dogs to average dogs
[#permalink]
Show Tags
06 Mar 2019, 07:45
A sufficient algebraic approach has already been provided by previous users, I used a rather unorthodox way of solving this. So by afternoon we have a new ratio of l:a of 4/5 and a greater ratio of l:e compared to the morning one. In the morning, it was 2:8, so i fathomed it to be e.g. 3:8. Next, i combined the ratios to get a total of 12:15:32 ratio with a total of 59 dogs. Now, the question states that there are fewer than 30 dogs, so in our scenario we are good to continue (59<60). 32/59 ~ 32/60 ~= 0,53 so it needs to be a bit higher due to all of our rounding up/downs, so 0,55 or 55%. Not the best way to go about it, neither the most foulproof, but if it works  it works.
_________________
 GMAT Prep #1 CAT (Apr 2019) : 640 (Q48, V30)  GMAT Prep #1 CAT (early Oct 2019  post hiatus) : 680 (Q48, V34)  MGMAT CAT #1 (mid Oct 2019) : 640 (Q44, V34)
Still not there.
If you're reading this, we've got this.




Re: At a local beach, the ratio of little dogs to average dogs
[#permalink]
06 Mar 2019, 07:45






