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Bowls X and Y each contained exactly 2 jelly beans, each of

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Bowls X and Y each contained exactly 2 jelly beans, each of [#permalink]

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Bowls X and Y each contained exactly 2 jelly beans, each of which was either red or black. One of the jelly beans in bowl X was exchanged with one of the jelly beans in bowl Y. After the exchange, were both of the jelly beans in bowl X black?

(1) Before the exchange, bowl X contained 2 black jelly beans.
(2) After the exchange, bowl Y contained 1 jelly bean of each color.
[Reveal] Spoiler: OA

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Re: Bowls X and Y each contained exactly 2 jelly beans, each of [#permalink]

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New post 08 Apr 2012, 10:13
boomtangboy wrote:
Bowls X and Y each contained exactly 2 jelly beans, each of which was either red or black. One of the jelly beans in bowl X was exchanged with one of the jelly beans in bowl Y. After the exchange, were both of the jelly beans in bowl X black?

(1) Before the exchange, bowl X contained 2 black jelly beans.
(2) After the exchange, bowl Y contained 1 jelly bean of each color.


Consider two cases for (1)+(2):

Initially X={BB} and Y={BR} --> B was exchanged with B --> X={BB} and Y={BR}: answer is YES;
Initially X={BB} and Y={RR} --> B was exchanged with R --> X={BR} and Y={BR}: answer is NO.

Answer: E.
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Re: Bowls X and Y each contained exactly 2 jelly beans, each of [#permalink]

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New post 19 Nov 2013, 15:17
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Re: Bowls X and Y each contained exactly 2 jelly beans, each of [#permalink]

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New post 19 Nov 2013, 21:48
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1) NS, because it gives no information on X after the exchange.
2) NS, because the initial for both X and Y could be the following:
X=RR Y=BB
X=RB Y=BB

1+2) NS
Case 1)
Before
X=BB Y=RR

After
Y=BR Y=RB

Case 2)
Before
X=BB Y=RB

After
X=BB Y=RB

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Re: Bowls X and Y each contained exactly 2 jelly beans, each of [#permalink]

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New post 24 Dec 2013, 02:21
I used very simple cases and got to the conclusion real quick.
Before
X=RR Y=RR

After
Y=RR Y=RR

Next Case
Before
X=BB Y=RR

After
X=BR Y=RB

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Re: Bowls X and Y each contained exactly 2 jelly beans, each of [#permalink]

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New post 27 Jan 2015, 19:20
Question: how do you know they are not "exclusive". I misunderstood the question as meaning that there are 2 black and 2 reds, and thus had everything wrong. What clue can you pick up to know that there can be any combination of colors?

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Re: Bowls X and Y each contained exactly 2 jelly beans, each of [#permalink]

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New post 22 Mar 2016, 10:02
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Bowls X and Y each contained exactly 2 jelly beans, each of [#permalink]

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New post 11 Jul 2017, 22:32
boomtangboy wrote:
Bowls X and Y each contained exactly 2 jelly beans, each of which was either red or black. One of the jelly beans in bowl X was exchanged with one of the jelly beans in bowl Y. After the exchange, were both of the jelly beans in bowl X black?

(1) Before the exchange, bowl X contained 2 black jelly beans.
(2) After the exchange, bowl Y contained 1 jelly bean of each color.


This question tests the general ability to think of counterexamples

It cannot be (1) alone because before exchange X=BB with Y=RR and Y=BR give different results for X
It cannot be (2) alone because after exchange Y=BR can come from X= BB with Y=RR and Y=BR and can give different results for X
It cannot be (1) and (2) together also because before exchange X=BB with Y=RR and Y=BR can give different results for X with Y=BR after exchange

So the answer is E

Note: Try to use the same counter example as far as possible.
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Bowls X and Y each contained exactly 2 jelly beans, each of   [#permalink] 11 Jul 2017, 22:32
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