Bunuel wrote:
For any 3 given numbers, which of the following is always equivalent to adding the 3 numbers together and then dividing the sum by 3?
I. Ordering the 3 numbers numerically, from highest to lowest, and then selecting the middle number.
II. Dividing each of the numbers by 3 and then adding the results together.
III. Multiplying each number by 6, adding the resulting products together, and then dividing the sum by 9.
A. I only
B. II only
C. I and II only
D. II and III only
E. None of the above
Let's take the three numbers as a,b and c, as per the stem, it is given that adding three number and dividing the numbers by 3 i.e. a+b+c/3 ---eq 1.
Now we need to check which of the following options are equal
I. Ordering the 3 numbers numerically, from highest to lowest, and then selecting the middle number.
Here we can take a>b>c or b>c>a or c>a>b, then we asked to take the middle number, the number can be b,c or a respectively and this is not equal to eq1.
II. Dividing each of the numbers by 3 and then adding the results together.
a/3, b/3 and c/3 => we get a+b+c/3 ---equal to eq1.
III. Multiplying each number by 6, adding the resulting products together, and then dividing the sum by 9.
6a,6b and 6c then adding and dividing by 9 => 6(a+b+c)/9 => 2(a+b+c)/3 and this is not equal to eq1.
Only option 2 is looks good.
IMO B is correct answer..
OA please...will correct if I missed anything..