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For any integers a and b, min(a, b) and max(a, b) denote the minimum a

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For any integers a and b, min(a, b) and max(a, b) denote the minimum a [#permalink]

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For any integers a and b, min(a, b) and max(a, b) denote the minimum and maximum of a and b, respectively. For example, min(1, 2) = 1 and max(1, 2) = 2. For the integer x, what is the value of max (x, 8)?

(1) max(x^2, x) = 16

(2) min(9, x) = x
[Reveal] Spoiler: OA

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Kudos [?]: 132643 [0], given: 12326

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For any integers a and b, min(a, b) and max(a, b) denote the minimum a [#permalink]

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New post 13 Sep 2017, 00:48
Find : Value of max (x, 8)= ?

(1) max(x^2, x) = 16
Always x^2 > x
ie here x^2 = 16
x= -4 or 4
For both values of x max (x,8 )= 8
max (-4,8) =8 and max (4,8 ) =8
Sufficient

(2) min(9, x) = x
Here minimum of x and 9 is x
=> x<9
As x is an integer
so maximum value of x =8 and x =<8
so always max (x,8) =8
as is x=8 => max (8,8) =8
if x <8 => max (x,8) =8

Sufficient

Answer: D

Kudos [?]: 80 [0], given: 65

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For any integers a and b, min(a, b) and max(a, b) denote the minimum a [#permalink]

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New post 13 Sep 2017, 01:14
Nikkb wrote:
Find : Value of max (x, 8)= ?

(1) max(x^2, x) = 16
Always x^2 > x
ie here x^2 = 16
x= -4 or 4
For both values of x max (x,8 )= 8
max (-4,8) =8 and max (4,8 ) =8
Sufficient

(2) min(9, x) = x
Here minimum of x and 9 is x
=> x<9
As x is an integer
so maximum value of x =8 and x =<8
so always max (x,8) =8
as is x=8 => max (8,8) =8
if x <8 => max (x,8) =8

Sufficient

Answer: D


I don't agree with part (2) here. Min (9,x) => x<=9 , it may be 9,8,7..
So we cannot be sure of the answer using option B.

Kudos [?]: 0 [0], given: 33

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Re: For any integers a and b, min(a, b) and max(a, b) denote the minimum a [#permalink]

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New post 13 Sep 2017, 01:28
Harsha109 wrote:
Nikkb wrote:
Find : Value of max (x, 8)= ?

(1) max(x^2, x) = 16
Always x^2 > x
ie here x^2 = 16
x= -4 or 4
For both values of x max (x,8 )= 8
max (-4,8) =8 and max (4,8 ) =8
Sufficient

(2) min(9, x) = x
Here minimum of x and 9 is x
=> x<9
As x is an integer
so maximum value of x =8 and x =<8
so always max (x,8) =8
as is x=8 => max (8,8) =8
if x <8 => max (x,8) =8

Sufficient

Answer: D


I don't agree with part (2) here. Min (9,x) => x<=9 , it may be 9,8,7..
So we cannot be sure of the answer using option B.


True . I missed the point of x =9.:(

Answer should be A.

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Re: For any integers a and b, min(a, b) and max(a, b) denote the minimum a [#permalink]

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New post 13 Sep 2017, 14:41
Quote:
I don't agree with part (2) here. Min (9,x) => x<=9 , it may be 9,8,7..
So we cannot be sure of the answer using option B.


Integers are a and b. So two different integers.

Kudos [?]: 27 [0], given: 92

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Re: For any integers a and b, min(a, b) and max(a, b) denote the minimum a [#permalink]

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New post 13 Sep 2017, 23:32
hwgmat2015 wrote:
Quote:
I don't agree with part (2) here. Min (9,x) => x<=9 , it may be 9,8,7..
So we cannot be sure of the answer using option B.


Integers are a and b. So two different integers.


Question stem did not say that a and b are "distinct" integers. Its just said they are integers.
so a and b can be equal.
There is no limitation on a and b as per question stem other than integer part.

Kudos [?]: 80 [0], given: 65

Re: For any integers a and b, min(a, b) and max(a, b) denote the minimum a   [#permalink] 13 Sep 2017, 23:32
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