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For positive integers a, b, and c, where a<b<c, the product abc has ex [#permalink]
Bunuel wrote:
For positive integers a, b, and c, where a<b<c, the product abc has exactly three prime factors. What is the maximum number of prime factors of a?

A. 0
B. 1
C. 2
D. 3
E. 4


for maximum no. of prime factors of a , it should be multiple of three prime nos.(since abc has only three prime factors)
and b &c could have any number of those three prime factors in a.

say if a =5^x * 7^y * 2^z
then b = 5^x * 7^y or any such prime combinations
& c= 5^x or 7^y or any combination as per condition a<b<c

thus a have max. of 3 prime factors

Ans D
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Re: For positive integers a, b, and c, where a<b<c, the product abc has ex [#permalink]
Bunuel wrote:
For positive integers a, b, and c, where a<b<c, the product abc has exactly three prime factors. What is the maximum number of prime factors of a?

A. 0
B. 1
C. 2
D. 3
E. 4


Hi GMATPrepNow,

Can you throw some light on these kinds of problem?

The easiest way to deal?
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Re: For positive integers a, b, and c, where a<b<c, the product abc has ex [#permalink]
Nice trap question.

The product result has exactly three prime factors.

The question doesn’t say that one prime factor comes from each number, the 3 prime factors can be present in all three value of A < B < C

A = (2) (3) (5)

B = (2)^2 (3)^2 (5)

C = (2)^3 (3)^3 (5)

Result of multiplication:

ABC = (2)^6 * (3)^6 * (5)^3

Condition is met- Result of ABC is divisible by exactly 3 prime factors 2, 3, and 5

And A can have all 3 prime factors

Posted from my mobile device
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Re: For positive integers a, b, and c, where a<b<c, the product abc has ex [#permalink]
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Re: For positive integers a, b, and c, where a<b<c, the product abc has ex [#permalink]
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