archish3113 wrote:

GMATinsight:

Statement 2: Each of the four shaded regions between the square and the circle has an area equal to 9 – 9/4*π.

i.e. (1/4[(2r)2−πr2]=9−(9/4)π(1/4[(2r)2−πr2]=9−(9/4)π

i.e. r = 3

i.e. r is NOT greater than 4 hence

Hello, could you please explain statement 2:

LHS of i.e. (1/4[(2r)2−πr2]=9−(9/4)π

How did you arrive at it?

archish3113One shaded portion at one of the corners = (1/4)*(Area of Square - Area of Circle) = \((1/4)*[(2r)^2−πr^2]=9−(9/4)π\)

Side of the square = 2r i.e. area of square = \((2r)^2\)

I hope this helps!!!

P.S. The Circle is inscribed in square i.e. Circle is tightly packed and touching all sides of teh square

_________________

Prosper!!!

GMATinsight

Bhoopendra Singh and Dr.Sushma Jha

e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772

Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi

http://www.GMATinsight.com/testimonials.html

ACCESS FREE GMAT TESTS HERE:22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION