filipembribeiro
If it is assumed that each of the n/4 production workers in a factory assembles one instrument every t minutes and the rest of the workers is 50% faster. How many instruments does the factory assemble in 8.5 hours of production?
A) \(\frac{2805n}{4t}\)
B) \(\frac{2805t}{4n}\)
C) \(2805nt\)
D) \(\frac{8.5t}{60} * (\frac{n}{4} + \frac{3n}{4})\)
E) \(\frac{8.5n}{60t} * (\frac{11}{4})\)
We have to assume that the total number of workers in the factory is n, because, otherwise, the problem would be unsolvable.
In the
slow subgroup (which consists of n/4 workers), we have:
rate of 1 worker = work/time = 1/t items per minute
rate of n/4 workers = (n/4)(1/t) = n/4t items per minute
time = 8.5 hours = 510 minutes
total work = rate × time = (n/4t)(510) = 510n/4t items
In the
fast subgroup (which consists of 3n/4 workers), we have:
rate of 1 worker = (3/2)(1/t) = 3/2t items per minute
rate of 3n/4 workers = (3n/4)(3/2t) = 9n/8t items per minute
time = 8.5 hours = 510 minutes
total work = rate × time = (9n/8t)(510) = 2295n/4t items
So, the total work done by the two subgroups in 8.5 hours is:
510n/4t + 2295n/4t = 2805n/4t items
Answer: A