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Re: If p^2, a perfect square number, is divisible by 5, and q, an integer, [#permalink]
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Stem 1: p^2 is a divisible by 5 means p is either a multiple of 5 or 10.
Stem 2: q is not divisible by 5 means it any be any number not ending with 5 or 0.

Answer choice analysis:

(A) pq+5 - can never be true as the number will never end in a zero

(B) p+q - can never be true, as q is not a multiple of 5

(C) 2(p+5q) - this will always be true, as 2p will always end with a zero (as p is a multiple of 5 or 10) and 10q will definitely end in zero. so their sum will always be divisible by 10.

(D) 2(5p+q) - can never be true because of q

(E) p^2+5q - can be true in only some cases (when p is a multiple of 10 and q is an even number)

Hence C is the answer
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Re: If p^2, a perfect square number, is divisible by 5, and q, an integer, [#permalink]
IMO C

P^2 = a perfect square and a multiple of 5

P^2 = 25, 125 , 625, ........... (P = 5, 15, 25........)

q = an integer not a multiple of 5

Multiples of 10 - The units digit = 0

A. pq + 5 >>>> 5 (4) + 5 = 25 >> not a multiple of 10
B. P + q >>>>> 5 + 1 = 6 >> not a multiple of 10
C. 2(p+5q) >>> 10 p + 10 q >> Always a multiple of 10

(D) 2(5p+q) >> 10 P + q >>> q can be 1, 2, 3, >> need not be a multiple of 10

(E) p^2+5q >>> 125 + 5 (2) = 135 >> not a multiple of 10
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Re: If p^2, a perfect square number, is divisible by 5, and q, an integer, [#permalink]
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