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Re: If p^2, a perfect square number, is divisible by 5, and q, an integer, [#permalink]
Expert Reply
We have no information at all about whether p and q are even or odd, but we're looking for an answer divisible by 10, so an answer that is certainly even. The only candidates are C and D.

The answer must also be divisible by 5. We know p is divisible by 5, since p^2 is. q is not divisible by 5, but 5q clearly is, and p + 5q is the sum of two multiples of 5, so must also be a multiple of 5. So 2(p + 5q) will be a multiple of 10, and C is the answer.
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Re: If p^2, a perfect square number, is divisible by 5, and q, an integer, [#permalink]
IMO C

P^2 = a perfect square and a multiple of 5

P^2 = 25, 125 , 625, ........... (P = 5, 15, 25........)

q = an integer not a multiple of 5

Multiples of 10 - The units digit = 0

A. pq + 5 >>>> 5 (4) + 5 = 25 >> not a multiple of 10
B. P + q >>>>> 5 + 1 = 6 >> not a multiple of 10
C. 2(p+5q) >>> 10 p + 10 q >> Always a multiple of 10

(D) 2(5p+q) >> 10 P + q >>> q can be 1, 2, 3, >> need not be a multiple of 10

(E) p^2+5q >>> 125 + 5 (2) = 135 >> not a multiple of 10
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Re: If p^2, a perfect square number, is divisible by 5, and q, an integer, [#permalink]
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