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If P = S/1+nr and P, S, n, and r are positive numbers, then in terms
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08 Nov 2018, 05:42
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If \(P = \frac{S}{1+nr}\) and \(P, S, n,\) and \(r\) are positive numbers, then in terms of \(P, S\) and \(r\) what does \(n\) equal? (A) \(\frac{SP}{Pr}\) (B) \(\frac{S}{rP}  1\) (C) \(\frac{SP}{r}\) (D) \(\frac{S}{P}  r\) (E) \(\frac{Pr}{S}  1\) Project PS Butler : Question #06 Subscribe to get Daily Email  Click Here  Subscribe via RSS  RSS
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Re: If P = S/1+nr and P, S, n, and r are positive numbers, then in terms
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08 Nov 2018, 06:29
HKD1710 wrote: If \(P = \frac{S}{1+nr}\) and \(P, S, n,\) and \(r\) are positive numbers, then in terms of \(P, S\) and \(r\) what does \(n\) equal? (A) \(\frac{SP}{Pr}\) (B) \(\frac{S}{rP}  1\) (C) \(\frac{SP}{r}\) (D) \(\frac{S}{P}  r\) (E) \(\frac{Pr}{S}  1\) Project PS Butler : Question #06 Subscribe to get Daily Email  Click Here  Subscribe via RSS  RSSWe need to find N in terms of P, R , S \(P = \frac{S}{1+nr}\) divide both sides by 1+nr \(\frac{P}{(1+NR)}= S\) \(S= P+PNR\) \(SP = PNR\) divide by PR \(\frac{SP}{PR}= N\) \(N = \frac{SP}{PR}\) IMO: A




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Re: If P = S/1+nr and P, S, n, and r are positive numbers, then in terms
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08 Nov 2018, 06:57
P * (1+nr) = S 1 + nr = S/P
nr = S/P  1
nr = SP/P
n = SP/Pr
Answer choice A
Try n = 1, r = 2 and s = 6
P = 6/(1+2) =6/3 = 2
If we rearrange the first formula it would be 6  2 = 4/(2*2) = 4/4 = 1



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Re: If P = S/1+nr and P, S, n, and r are positive numbers, then in terms
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08 Nov 2018, 10:39
HKD1710 wrote: If \(P = \frac{S}{1+nr}\) and \(P, S, n,\) and \(r\) are positive numbers, then in terms of \(P, S\) and \(r\) what does \(n\) equal? (A) \(\frac{SP}{Pr}\) (B) \(\frac{S}{rP}  1\) (C) \(\frac{SP}{r}\) (D) \(\frac{S}{P}  r\) (E) \(\frac{Pr}{S}  1\) Project PS Butler : Question #06 Subscribe to get Daily Email  Click Here  Subscribe via RSS  RSS\(P = \frac{S}{1+nr}\) or, \(\frac{P}{S} = \frac{1}{1+nr}\) or, \(\frac{S}{P} = 1+nr\) or, \(\frac{S}{P} 1= nr\) or, \(\frac{SP}{Pr} =n\).... Ans A.
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Re: If P = S/1+nr and P, S, n, and r are positive numbers, then in terms
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09 Nov 2018, 09:38
u1983 wrote: HKD1710 wrote: If \(P = \frac{S}{1+nr}\) and \(P, S, n,\) and \(r\) are positive numbers, then in terms of \(P, S\) and \(r\) what does \(n\) equal? (A) \(\frac{SP}{Pr}\) (B) \(\frac{S}{rP}  1\) (C) \(\frac{SP}{r}\) (D) \(\frac{S}{P}  r\) (E) \(\frac{Pr}{S}  1\) Project PS Butler : Question #06 Subscribe to get Daily Email  Click Here  Subscribe via RSS  RSS\(P = \frac{S}{1+nr}\) => \(\frac{S}{P} = 1+nr\) => \(\frac{S}{P} 1= nr\) => \(\frac{SP}{Pr} =n\) A is the correct Answer
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Re: If P = S/1+nr and P, S, n, and r are positive numbers, then in terms
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11 Nov 2018, 20:23
HKD1710 wrote: If \(P = \frac{S}{1+nr}\) and \(P, S, n,\) and \(r\) are positive numbers, then in terms of \(P, S\) and \(r\) what does \(n\) equal?
(A) \(\frac{SP}{Pr}\)
(B) \(\frac{S}{rP}  1\)
(C) \(\frac{SP}{r}\)
(D) \(\frac{S}{P}  r\)
(E) \(\frac{Pr}{S}  1\) Simplifying, we have: P(1 + nr) = S P + Pnr = S Pnr = S  P n = (S  P)/Pr Answer: A
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Re: If P = S/1+nr and P, S, n, and r are positive numbers, then in terms
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03 Feb 2019, 05:11
HKD1710 wrote: If \(P = \frac{S}{1+nr}\) and \(P, S, n,\) and \(r\) are positive numbers, then in terms of \(P, S\) and \(r\) what does \(n\) equal?
(A) \(\frac{SP}{Pr}\)
(B) \(\frac{S}{rP}  1\)
(C) \(\frac{SP}{r}\)
(D) \(\frac{S}{P}  r\)
(E) \(\frac{Pr}{S}  1\)
Substitute the values carefully P =S / (1+nr) S = 4 n = 3 r =1, P = 1 We need to find an expression which will give n=3 A does that
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Re: If P = S/1+nr and P, S, n, and r are positive numbers, then in terms
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