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If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) =

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If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) = [#permalink]

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New post 17 Sep 2017, 02:45
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Question Stats:

81% (01:18) correct 19% (02:10) wrong based on 54 sessions

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Re: If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) = [#permalink]

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New post 17 Sep 2017, 03:09
X(x+.25)=.5, either x=.5 or x=.25. Now substituting these values in the required equation, x(4x+1)= either 1.5 or .5. So answer is A.

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Re: If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) = [#permalink]

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New post 17 Sep 2017, 03:47
Sorry. Correcting the answer is B i.e. 2

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Re: If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) = [#permalink]

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New post 17 Sep 2017, 06:55
Bunuel wrote:
If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) =

A. 0.5
B. 2
C. 3.5
D. 4
E. 0


x^2+1/4x= 1/2;

4x^2+x= 2 ==> x(4x+1)= 2

Ans:B
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If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) = [#permalink]

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New post 17 Sep 2017, 14:01
Bunuel wrote:
If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) =

A. 0.5
B. 2
C. 3.5
D. 4
E. 0

\(x^2 + 0.25x - 0.5 = 0\)

Multiply by 4: prompt's second expression is a factored version of \(4x^2 + x\). That expression = \((4)(x^2 + 0.25x)\) -- i.e., (4) * the first two terms of the quadratic equation

\((4)x^2 + (4)0.25x - (4)0.5 = 0\)
\(4x^2 + x - 2 = 0\)
\(4x^2 + x = 2\)
\(x(4x + 1) = 2\)

Answer B
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Re: If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) = [#permalink]

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New post 18 Sep 2017, 10:53
x^2 + .25x -.5=0
can be written as x^2 + x/4 -5/10=0
now, x( x+1/4)=5/10
multiple by 4 on both sides
you get 4x^2+x=2 i.e x(4x+1)=2
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Re: If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) = [#permalink]

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New post 18 Sep 2017, 11:03
x^2 + (x/4) =1/2
x(4x +1) = 2 so Ans is B.
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Re: If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) = [#permalink]

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New post 22 Sep 2017, 10:45
Bunuel wrote:
If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) =

A. 0.5
B. 2
C. 3.5
D. 4
E. 0


We need to determine the value of x(4x + 1) = 4x^2 + x.

Multiplying the equation x^2 + 0.25x - 0.5 = 0 by 4, we have:

4x^2 + x - 2 = 0

4x^2 + x = 2

Answer: B
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Re: If x^2 + 0.25x - 0.5 = 0, then x(4x + 1) =   [#permalink] 22 Sep 2017, 10:45
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