Bunuel wrote:

If x is a positive integer, what is the value of x ?

(1) \(x^2=\sqrt{x}\)

(2) \(\frac{n}{x} = n\) and \(n\neq 0\)

Given \(x > 0\) (integer)

Statement 1: \(x^2 = \sqrt{x}\)

Squaring both sides: \(x^4 = x\)

\(x^4 - x = 0\)--- \(x (x^3 - 1) = 0\)

Solving for x

x= 0 or x = 1 , As x can't be 0 as x is positive as per question stem, the only valid value is "1" Sufficient.

Statement 2: \(\frac{n}{x}\) \(= n\) & \(n\neq{0}\)

x can only be "1" for statement-2 to be true.

Sufficient. IMO Answer is (D). Updated answer (forgot to consider the question stem

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