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# If y + 40x + 2 = 0, what is the value of xy?

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Intern
Joined: 06 Oct 2012
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If y + 40x + 2 = 0, what is the value of xy?  [#permalink]

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Updated on: 06 Sep 2017, 09:31
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Difficulty:

15% (low)

Question Stats:

84% (01:01) correct 16% (01:01) wrong based on 63 sessions

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If y + 40x + 2 = 0, what is the value of xy?

(1) 16x = –4y + 28

(2) 13y = 91 – 52x

Originally posted by dheerajkaushik90 on 06 Sep 2017, 09:26.
Last edited by Bunuel on 06 Sep 2017, 09:31, edited 2 times in total.
Intern
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Re: If y + 40x + 2 = 0, what is the value of xy?  [#permalink]

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06 Sep 2017, 09:50
Since both the equations are simplified to form:

4x+y =7

How do we get xy in this case?
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Re: If y + 40x + 2 = 0, what is the value of xy?  [#permalink]

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06 Sep 2017, 10:05
1. We have two equation. Sufficient to find x and y values

Eliminate BCE

2. We have two equation. Sufficient to find x and y values

Hence, its D

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Intern
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Re: If y + 40x + 2 = 0, what is the value of xy?  [#permalink]

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06 Sep 2017, 10:47
Statement 1 - solving the two equations x=-1/4 & y=8 hence xy=-2
Statement 2 - since it the same line hence the values of x & y will be the same as from statement 1. Hence answer is D

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Re: If y + 40x + 2 = 0, what is the value of xy?  [#permalink]

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07 Sep 2017, 07:08
dheerajkaushik90 wrote:
If y + 40x + 2 = 0, what is the value of xy?

(1) 16x = –4y + 28

(2) 13y = 91 – 52x

$$y + 40x + 2 = 0$$ --------- (i)

(1) $$16x = –4y + 28$$

$$4x = -y + 7$$

$$y + 4x = 7$$ -------- (ii)

Subtracting (i) and (ii) we can find the value of $$x$$ and $$y$$. Hence we can find the value of $$xy$$.

Hence I is Sufficient.

(2) $$13y = 91 – 52x$$

$$y = 7 - 4x$$

$$y + 4x = 7$$ ---------- (iii)

Subtracting (i) and (iii) we can find the value of $$x$$ and $$y$$. Hence we can find the value of $$xy$$.

Hence II is Sufficient.

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Re: If y + 40x + 2 = 0, what is the value of xy?  [#permalink]

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07 Sep 2017, 08:21
What is the OA for the question

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Re: If y + 40x + 2 = 0, what is the value of xy?  [#permalink]

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11 May 2018, 08:50
Top Contributor
dheerajkaushik90 wrote:
If y + 40x + 2 = 0, what is the value of xy?

(1) 16x = –4y + 28

(2) 13y = 91 – 52x

Target question: What is the value of xy?

Given: y + 40x + 2 = 0
Rearrange to get: 40x + y = -2

IMPORTANT: We are given one linear equation. If we given a different linear equation, then we can be certain to solve the system of equations for x and y, which means we can determine the value of xy
So, we need only determine whether each statement provides a linear equation that is different from the given linear equation (40x + y = -2)

Statement 1: 16x = –4y + 28
Divide both sides by 4 to get: 4x = -y + 7
Add y to both sides: 4x + y = 7
This second linear equation is different from the given linear equation (40x + y = -2)
This means we COULD solve the system of equations for x and y, which means we COULD determine the value of xy
Since we COULD answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: 13y = 91 – 52x
Divide both sides by 13 to get: y = 7 - 4x
Add 4x to both sides: 4x + y = 7
This is the same equation that we have in statement 1.
So, if statement 1 is sufficient, we can also be certain that statement 2 is SUFFICIENT

Cheers,
Brent
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Re: If y + 40x + 2 = 0, what is the value of xy? &nbs [#permalink] 11 May 2018, 08:50
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