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Bunuel
­If \(|y + 5| < 1 - x\) and \(x\) is a non-zero integer, what is the value of \(\frac{|x| + 5}{5 - x}\) ?

A. -5
B. -1
C. 0
D. 1
E. Cannot be determined from the given information­

 
­
\(|y + 5| < 1 - x\)

As the value of mod is always non-negative, for the condition to hold true, x must be either zero or negative. 

As the question stem mentions that x is not zero, \(x\) is negative. 

\(\frac{|x| + 5}{5 - x}\)

= \(\frac{(-x) + 5}{5 - x}\)

= 1

Option D­
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Bunuel
­If \(|y + 5| < 1 - x\) and \(x\) is a non-zero integer, what is the value of \(\frac{|x| + 5}{5 - x}\) ?

A. -5
B. -1
C. 0
D. 1
E. Cannot be determined from the given information­

­
Bunuel: I think there is a typo and y should be replaced by x

­|x + 5| < 1 - x

Since ­|x + 5| must be non-negative therefore, 1-x ≥0 i.e. x ≤ 1

For positive value of x, there is no Possible solution of ­|x + 5| < 1 - x
For Negative value of x (@x = -a), ­5 - a < 1 + a
i.e. a > 2 i.e. x < -2

Question: (|x| + 5)/ (5 - x)

Let, x = -3, (|x| + 5)/ (5 - x) = 8/8 = 1
Let, x = -4, (|x| + 5)/ (5 - x) = 9/9 = 1

Answer: Option D­
­
gmatophobia
Bunuel
­If \(|y + 5| < 1 - x\) and \(x\) is a non-zero integer, what is the value of \(\frac{|x| + 5}{5 - x}\) ?

A. -5
B. -1
C. 0
D. 1
E. Cannot be determined from the given information­


­
|x + 5| < 1 - x

Squaring both sides, we get

\(x^2 + 25 + 10x < 1 + x^2 - 2x\)

\(12x < -24\)

\(x < -2\)

Hence, \(x\) is negative.

\(\frac{|x| + 5}{5 - x}\)

= \(\frac{(-x) + 5}{5 - x}\)

= 1

Option D
­

No typo there. Would anyone else like to try?­
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Bunuel
No typo there. Would anyone else like to try?­
Argg! Apologies for the oversight   :facepalm_man:.

Edited my solution now :)­
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Bunuel
­If \(|y + 5| < 1 - x\) and \(x\) is a non-zero integer, what is the value of \(\frac{|x| + 5}{5 - x}\) ?

A. -5
B. -1
C. 0
D. 1
E. Cannot be determined from the given information­


This is a PS Butler Question

­
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­If \(|y + 5| < 1 - x\) and \(x\) is a non-zero integer, what is the value of \(\frac{|x| + 5}{5 - x}\) ?

\(0<=|y + 5| < 1 - x\)
1 - x >0
x < 1;
x<0

\(\frac{|x| + 5}{5 - x} = \frac{-x + 5}{5 - x}  = 1 \)

IMO D
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­If \(|y + 5| < 1 - x\) and \(x\) is a non-zero integer, what is the value of \(\frac{|x| + 5}{5 - x}\) ?

A. -5
B. -1
C. 0
D. 1
E. Cannot be determined from the given information

It suggests that x < 0 as an absolute value is positive.
Now any value(after checking two values we know the answer) we take for x and solve \(\frac{|x| + 5}{5 - x}\) we get only one answer.

Answer D.
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