1. Since Y is even , it must have at least one factor of 2 .

\(Y^{2}\)= Y*Y

So Y^2 will have at least 2 powers of 2 i.e 2^2 . From each Y , we can factor out a 2. Hence, it will be divisible by 4=2^2

2. \(Y ^ {3}\) is divisible by 4 =2^2

Y^3 is divisible by 4 .So, Y^3 will contain 2^2 . Since , Y is an integer so each Y should contain at least a single factor of 2.

Hence, \(Y^{2}\)should contain at least 2^2

So , answer is D

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