Answer: D

Given:

G1+G2+G3+B(Tall)+B(Short)= 600

B(Tall)= 120 that means G1+G2+G3+B(S)= 460

What we have to find is (G1+G2+G3)/3< 117 (Yes or No)

Statement A

B(S)= 130

This gives us the age of both boys and we can find the sum of the ages of all the three girls. We will divide the sum by 3 and that will give us the average height of the girls. Hence sufficient for us to answer the question

Statement 2

Shortest members of the group are the two girls and they both have the same height which is 110

G1 (shortest) + G2(other shortest) + G3 + B(Tallest) + B(Short)= 600

110+110+ G3+140+ B(S)=600

G3+B(S)= 240

we know that each G3 & B(S) have a height above 110. Therefore we can take two cases.

Case-I= G(3) has a height of 129 and B(S) has a height of 111

(G1+G2+G3)/3= (110+110+129)/3 = 116.3.. which is less than 117

Case-I= G(3) has a height of 111 and B(S) has a height of 129

(G1+G2+G3)/3= (110+110+111)/3 = 110.3.. which is also less than 117

Hence statement two is sufficient to answer the question. Therefore the answer is D (each statement alone is sufficient)

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