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In the expression above, if xn#0, what is the value of S?
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18 Dec 2012, 08:13
18 Dec 2012, 08:13
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\(S=\frac{\frac{2}{n}}{\frac{1}{x}+\frac{2}{3x}}\)
In the expression above, if xn ≠ 0, what is the value of S?
(1) x = 2n
(2) n = 1/2
In the expression above, if xn ≠ 0, what is the value of S?
(1) x = 2n
(2) n = 1/2
Re: In the expression above, if xn#0, what is the value of S?
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18 Dec 2012, 08:17
18 Dec 2012, 08:17
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\(S=\frac{\frac{2}{n}}{\frac{1}{x}+\frac{2}{3x}}\)
In the expression above, if xn#0, what is the value of S?
\(S=\frac{\frac{2}{n}}{\frac{1}{x}+\frac{2}{3x}}=\frac{\frac{2}{n}}{\frac{5}{3x}}=\frac{6x}{5n}\)
(1) x = 2n --> \(S=\frac{6x}{5n}=\frac{6*2n}{5n}=\frac{12}{5}\). Sufficient.
(2) n = 1/2. We need the value of x to answer the question. Not sufficient.
Answer: A.
In the expression above, if xn#0, what is the value of S?
\(S=\frac{\frac{2}{n}}{\frac{1}{x}+\frac{2}{3x}}=\frac{\frac{2}{n}}{\frac{5}{3x}}=\frac{6x}{5n}\)
(1) x = 2n --> \(S=\frac{6x}{5n}=\frac{6*2n}{5n}=\frac{12}{5}\). Sufficient.
(2) n = 1/2. We need the value of x to answer the question. Not sufficient.
Answer: A.
Re: In the expression above, if xn#0, what is the value of S?
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21 Dec 2013, 07:54
21 Dec 2013, 07:54
Hi Bunuel,
sorry for being imprecise and thanks for your quick answer.
I used the following approach:
\(S=\frac{\frac{2}{n}}{\frac{1}{x}+\frac{2}{3x}}\)
\(S= \frac{2}{n}(x+\frac{3x}{2})\)
\(S= \frac{2x}{n}+\frac{6x}{2n}\)
\(S= \frac{4x}{2n}+\frac{6x}{2n}=\frac{5x}{n}\)
Can you please tell me what is wrong with my approach?
Thanks a lot in advance.
sorry for being imprecise and thanks for your quick answer.
I used the following approach:
\(S=\frac{\frac{2}{n}}{\frac{1}{x}+\frac{2}{3x}}\)
\(S= \frac{2}{n}(x+\frac{3x}{2})\)
\(S= \frac{2x}{n}+\frac{6x}{2n}\)
\(S= \frac{4x}{2n}+\frac{6x}{2n}=\frac{5x}{n}\)
Can you please tell me what is wrong with my approach?
Thanks a lot in advance.
