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Re: In the figure above, ABCD is a square, and the two diagonal
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13 Jun 2015, 07:52
It's a good question! As pointed out in the official MGMAT explanation for this question (in the version I've seen, the answer choices are provided in decimals rather than square root form), estimation is an excellent way to solve this question. Problem Solving statements are always drawn to scale unless otherwise stated, and an estimation will clearly show that x is a little less than 1. Only one answer choice is less 1.



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Re: In the figure above, ABCD is a square, and the two diagonal
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06 Aug 2015, 09:51
a = area of the portion Just rearrange the figure and it becomes lot easier to solve this question .
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Re: In the figure above, ABCD is a square, and the two diagonal
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22 Oct 2015, 06:16
greatps24 wrote: In the figure above, ABCD is a square, and the two diagonal lines divide it into three regions of equal area. If AB = 3, what is the length of w, the perpendicular distance between the two diagonal lines? a. 3√2 – 2√3 b. 3√2 – √6 c. √2 d. 3√2 / 2 e. 2√3 – √6 Can you solve this in 2 min? Please check the figure for solution Answer: option A
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Re: In the figure above, ABCD is a square, and the two diagonal
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27 Feb 2016, 10:35
that's how I got to the answer: we can find the area of the triangles. we can find the sides of the triangles we can find the diagonal of the square
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Re: In the figure above, ABCD is a square, and the two diagonal
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23 Jan 2017, 06:31
Mgmat version is quite hard if you don't estimate. I found w=3√2  2√3, but spent 2 minutes to figure out what is the decimal version. I think this question is basically saying us you can use estimation in PS when you are stuck.



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Re: In the figure above, ABCD is a square, and the two diagonal
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18 Aug 2018, 10:38
How do you know the three areas are equal(How do you conclude that the middle area is equal to the area of the triangles)?




Re: In the figure above, ABCD is a square, and the two diagonal &nbs
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18 Aug 2018, 10:38



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