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If we translate the statement "Three quarters of all batches do not require additional heating" to the probability as following: 3/4 of a batch requires 0 heating and 1/4 of a batch requires 1 heating (worth 20 mins), and "half of all batches require a second mixing with hydrochloric acid, none requires the third" as 1/2 of a batch requires 1 mixing (20 mins) and 1/2 batch requires 2 mixing (40 minutes), the calculation for average time is as following:
30 mins + (3/4*0 +1/2* 20 mins) + 5 mins + (1/2 *20 mins+1/2 * 40 mins)+10+60 = 140 mins

For the stage, we count 1 for the rectangular box, the calculation will be 1+(3/4*0+1/4*1)+1+(1/2*1+1/2*2)+1+1 = 5.75.
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I have a doubt, would we not be taking into account the batches moving in parallel that is while 1/4 of the batch would be re heated (taking additional 20 mins) the rest of the batch would move to next stage

What effect this would create would be that during the movement of rest of batch would be covered in the re heating times
I.e while 1/4 of batch would be getting re heated, the rest of the batch would have finished with HCL mixing
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shauryahanda
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I have a doubt, would we not be taking into account the batches moving in parallel that is while 1/4 of the batch would be re heated (taking additional 20 mins) the rest of the batch would move to next stage

What effect this would create would be that during the movement of rest of batch would be covered in the re heating times
I.e while 1/4 of batch would be getting re heated, the rest of the batch would have finished with HCL mixing

The processing time for a single batch will stop when it has finished the Drying stage. So, even if there are some batches in the earlier stages, the average time required will not change.
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If we translate the statement "Three quarters of all batches do not require additional heating" to the probability as following: 3/4 of a batch requires 0 heating and 1/4 of a batch requires 1 heating (worth 20 mins), and "half of all batches require a second mixing with hydrochloric acid, none requires the third" as 1/2 of a batch requires 1 mixing (20 mins) and 1/2 batch requires 2 mixing (40 minutes), the calculation for average time is as following:
30 mins + (3/4*0 +1/2* 20 mins) + 5 mins + (1/2 *20 mins+1/2 * 40 mins)+10+60 = 140 mins

For the stage, we count 1 for the rectangular box, the calculation will be 1+(3/4*0+1/4*1)+1+(1/2*1+1/2*2)+1+1 = 5.75.

ptkm great explanation. Why are we only take care of 1/4 and not 2/4 as it has total 3/4?
Could you help clarify? Thanks
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The calculations of this question was hard. It required concepts of Sets, Weighted Average and LCM. Make the denominator of all fractions to be 12 (LCM of 4 and 3 for easy calculation)

- Two twelfth of the set require ONLY additional heating
- One twelfth of the set require BOTH additional heating and additional HCl mixing
- Five twelfth of the set require ONLY additional HCl mixing
- Four twelfth of the set require NOTHING at all.

Now, use weighted average's concept to solve question 1 and 2. If you require detailed solution, mention me and I will add it here.­
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­my solution in the picture attached!
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Vinit800HBS Sir Thank you for the detailed explanation. It was helpful.  :please:

Have two doubts. Could you clarify -
"2 units (1/2 of the batch) require additional HCL mixing. So, it adds 20 + 20 mins to the process."
- In this case, why not 2 units be processed in the same 20 mins? 

"2 units (1/2 of the batch) require additional HCL mixing. So, it adds 2 more stages to the process."
- In this case, why not it be adds just 1 stage, as both units have the same unique stage? (Stimulus also says that half of batch requires just one second mixing).

Thank you.­

chetan2u Sir please explain if possible.
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gclub1

Hi gclub1

Even if you combine 2 lots to perform the HCL mixing operation together, it will not alter the weighted avg

Additional time will be (20 min * 2 lots + 20 min) * 1 lot /( total lot = 4) = 15 min

So, the total time is 125+15 = 140 min

Happy Learning­
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I would do this way.

1) 30n + 20*(n/4) + 5n + 20n + 20(n/2)+ 10n + 60n =140n
Average = 140n/n = 140

2)n+n/4+n+n+n/2+n+n = 5n + 3n/4
Average = 5.75
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In the flowchart, each rectangular box represents a distinct stage in the production of a 50-kilogram batch of a specialty chemical. Decision points, which are not distinct stages, are represented by diamond shapes. The time required for each stage is indicated in minutes (min). There is no waiting time between stages. Three quarters of all batches do not require additional heating, while half of all batches require a second mixing with hydrochloric acid (HCL); none require a third.

From each drop-down menu, select the option that creates the most accurate statement based on the information provided.

The average time in minutes that a batch of ingredients to make it all the way through the process shown is:

The average number of stages that a batch undergoes is:

Attachment:
The attachment Capture.JPG is no longer available

Hi guys, I solved the graph problem using the method in the photo. What do you think of it? Was it effective and correct?

KarishmaB Bunuel GMATCoachBen bb
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macjas


In the flowchart, each rectangular box represents a distinct stage in the production of a 50-kilogram batch of a specialty chemical. Decision points, which are not distinct stages, are represented by diamond shapes. The time required for each stage is indicated in minutes (min). There is no waiting time between stages. Three quarters of all batches do not require additional heating, while half of all batches require a second mixing with hydrochloric acid (HCL); none require a third.

From each drop-down menu, select the option that creates the most accurate statement based on the information provided.

The average time in minutes that a batch of ingredients to make it all the way through the process shown is:

The average number of stages that a batch undergoes is:

Attachment:
Capture.JPG

How will we calculate average time taken?

Average time = Total time taken / No of batches

Say we have 4 batches. Basic time taken for each of the 4 batches will be 30 + 5 + 20 + 10 + 60 = 125 mins. For 2 batches, extra 20 mins will be required (1/2 batches need second mixing of HCl) and for 1 batch, additional 20 mins will be needed for additional heating (a quarter of all batches)

So Average time = Total time taken / No of batches = (4*125 + 2*20 + 1* 20)/4 = 140

Similarly, average number of stages = Total no of stages / No of batches

Of 4 batches, basic stages are 5, 2 batches need an additional stage of HCl mixing and 1 batch needs additional stage of Heating.

So Average number of stages = Total number of stages / No of batches = (4*5 + 2*1 + 1* 1)/4 = 5.75

Select 140 and 5.75

Here is a discussion on another Flowchart question: https://youtu.be/EwWZUiKLAZk

Gmatguy007 - From what I can figure out, this is pretty much what you have done too.
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