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Is 3^p > 2^q ? (1) q = 2p (2) q > 0

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Bunuel
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Is 3^p > 2^q ? (1) q = 2p (2) q > 0 [#permalink] New post   01 Jul 2018, 21:08
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A
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C
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E

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35% (medium)

Question Stats:

70% (01:36) correct 30% (01:32) wrong based on 399 sessions
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Is \(3^p > 2^q\) ?


(1) \(q = 2p\)

(2) \(q > 0\)
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C
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chetan2u
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Re: Is 3^p > 2^q ? (1) q = 2p (2) q > 0 [#permalink] New post   09 Apr 2022, 04:19
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Divsri wrote:
Bunuel chetan2u

What if p is considered as a fraction? There are no specifications given in the problem that p has to be an integer.

In the case that p= 1/2, then the answer will be E right.


p and q could be anything. The answer will always be NO.

\(3^p>2^q\)

\(3^{\frac{1}{2}}>2^1\)

\(1.7>2\)….NO

Answer will remain C.
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Re: Is 3^p > 2^q ? (1) q = 2p (2) q > 0 [#permalink] New post   01 Jul 2018, 22:59
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Bunuel wrote:
Is \(3^p > 2^q\) ?


(1) \(q = 2p\)

(2) \(q > 0\)


\(3^p > 2^q\) ?


(1) \(q = 2p\)..
\(3^p>2^q.........3^p>2^{2q}..........3^p>4^p\)
if p and q are positive ... NO.....\(3^2>4^2.....9>16\)
if p and q are negative ... YES.....\(3^{-2}>4^{-2}.....\frac{1}{9}>\frac{1}{16}\)
Insuff

(2) \(q > 0\)
Nothing about p
insuff

combined
always NO
suff

C
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Re: Is 3^p > 2^q ? (1) q = 2p (2) q > 0 [#permalink] New post   15 Aug 2020, 06:14
Bunuel wrote:
Is \(3^p > 2^q\) ?


(1) \(q = 2p\)

(2) \(q > 0\)


Hello guys!

Statement 1 says that,
\(q=2p,\)
\(p=\frac{q}{2}\)

Let's plug in numbers, using q=2
3^q/2 > 2^q
3^2/2 > 2^2
3^1> 4
It is not true that 3> 4

Let's plug in one more number for better validation, using q=0
3^q/2 > 2^q
3^0/2> 2^0
3^0>2^0
1>1
It is not true that 1>1

As we did not find a unique solution to this. This statement is not sufficient.

Statement 2 says that,
q>0
This statement alone does not help us, as it does not throw out any numbers.
This statement also is not sufficient.

Let's combine both the statements 1 and 2,
We can be definite on the fact that
3^p> 2^q is not true, which helps us to understand that statements 1 and 2 are sufficient.

Official Answer:- Option C

Thank you!

Regards,
Raunak Damle :thumbsup:
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Re: Is 3^p > 2^q ? (1) q = 2p (2) q > 0 [#permalink] New post   09 Apr 2022, 03:49
Bunuel chetan2u

What if p is considered as a fraction? There are no specifications given in the problem that p has to be an integer.

In the case that p= 1/2, then the answer will be E right.
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Re: Is 3^p > 2^q ? (1) q = 2p (2) q > 0 [#permalink] New post   11 Sep 2023, 20:27
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Re: Is 3^p > 2^q ? (1) q = 2p (2) q > 0 [#permalink]
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