Is m

Question

Is m < n?

(1) m < n^2

(2) |m| < n

ArunSharma12 · Answer

statement 1: m < n^2 when both are positive, n > m when both are negative then m > n not sufficient statement 2: |m| < n; this implies n is greater than distance of m from origin and n is always positive. this means regardless of the sign of m, n will always be greater than magnitude of m. sufficient. Ans: B

CareerGeek · Answer

(1) m < n^2 Case 1: m = 2. n = -3; —> m > n Case 2: m = 2, n = 3; —> m < n —> Insufficient (2) |m| < n Case 1: m = -2. n = 3; —> m < n Case 2: m = 2, n = 3; —> m < n —> m < n always —> Sufficient Option B Posted from my mobile device

Kinshook · Answer

Asked: Is m < n?

(1) m < n^2
n may or may not be <n^2
NOT SUFFICIENT

(2) |m| < n
0<|m|<n
|m| = m
m < n
SUFFICIENT

IMO B

tanushreegohain93 · Answer

I have a doubt in this question regarding statement 2

b) |m| < n (e.g |x|<2 meaning -2<x<2)

This means that -n <m <n so If I assume n = 5 or any other no. then the range is from -5 <m< 5 then m maybe less than n or greater than n
How is this statement sufficient. Please correct me if my reasoning is wrong.

Bunuel · Answer

Even your examples, gives m less than n (5 in your case). And yes, |m| < n means that -n <  m < n . Notice that you have an answer directly there:  m < n .

yashikaaggarwal · Answer

Well you can take it like |2|<5
Now. No matter whether its -2 or 2 both are less than 5.
So statement 2 is sufficient

Posted from my mobile device

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Is m < n? (1) m < n^2 (2) |m| < n

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