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Re: Is positive integer A greater than positive integer B? [#permalink]
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ans E...
1) it does not tell us anything about their value... a prime no say 61 may have lesser factors but still be >30,which has more factors..
insufficient..
2) it again tells us that the prime factor of A are more or same as B.. insufficient
combined insufficient... say A=2^5*3*5*17 and B=2*3*17^4... here a has more factors yet it is smaller
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Re: Is positive integer A greater than positive integer B? [#permalink]
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Here we go----

Best approach to solve these type of problems - pick values

St1: A has more factors than B does.

A = 12 = 2^2 * 3 ---> Number of factors 6
B = 49 = 7^2 ----> Number of factors 3

But B > A

Clearly not sufficient.

St2: Every prime factor of B is a factor of A.

B = 12 ---> Prime Factors-> 2,3
A = 6 ----> Prime factors-> 2,3

But B > A

Combining

A has more factors than B does
Every prime factor of B is a factor of A

Number of factors are given by multipying the prime factors of the given number after adding 1 to prime factors.

Every prime factor of B is a factor of A, and A has more factors.

b = 2 * 3 * (5)^10
a = 2^(8) * 3^(2) * 5

But b > a

option E is correct
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Re: Is positive integer A greater than positive integer B? [#permalink]
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Bunuel wrote:
Is positive integer A greater than positive integer B?

(1) A has more factors than B does.

(2) Every prime factor of B is a factor of A.

Kudos for a correct solution.



E

approach:
Question is A>B

from 1: A has more factors than B
let A = 12, B =13--> we end up with A having more factors than B
if A =13, B =12 --> B has more factors, 2 diff answers NSF

from 2:
try numbers:
A =13, B =69, we have A<B, still the prime factors of A and B are same.
if A = 20, B =10, then A> B and the condition still meets --> NSF

1+2:
still not sufficient as the number of factors does not tell anything on the size of the numbers from 1 (solution) and we still end up with case 2, which lead to 2 answers
NSF

E
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Is positive integer A greater than positive integer B? [#permalink]
How I got to E:

[1] A has more factors than B does.
Perhaps A has more factors, but these factors are of a small value.
E.g A=2*2*2 = 8
and B= 3*5 = 15

[2] Every prime factor of B is a factor of A.
To me this meant that A has all of the factors of B, plus some more.

So, if B=2*2*3, then A could be:
A=2*2*3*1. This would make A=B
A=2*2*3*1*5. This would make A>B.

For the same reasons [1] and [2] together are NS.
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Re: Is positive integer A greater than positive integer B? [#permalink]
Bunuel, the lesson of this question could be that more factors of a positive integer than another positive integer, doesn't mean that first integer is greater that the latter one.
Also that the inclusion of all prime factors of a positive integer in another positive integer, doesn't mean that first integer is greater that the latter one.
Please correct me if I misunderstood.
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Re: Is positive integer A greater than positive integer B? [#permalink]
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hatemnag wrote:
Bunuel, the lesson of this question could be that more factors of a positive integer than another positive integer, doesn't mean that first integer is greater that the latter one.


Yes, for example: 6 has four factors but is less than 7, which has 2 factors.

hatemnag wrote:
Also that the inclusion of all prime factors of a positive integer in another positive integer, doesn't mean that first integer is greater that the latter one.
Please correct me if I misunderstood.


Yes, it'll depend on powers of these primes.
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Is positive integer A greater than positive integer B? [#permalink]
Answer E

(1) A has more factors than B does.
- In Suff, As A can be any composite number and B can be a prime number greater than A and have number of factors (1) less than that of A OR B can be a prime number less than A and still number of factors(1) less than that of A.

(2) Every prime factor of B is a factor of A.
- In Suff, just knowing the every prime factors of A and B does not tell us which is greater

(1) + (2) =>
Let common prime factors be \((5,7)\)

Let A : \(5^4 * 7^2\) => no of factors \((4+1)(2+1) = 15\)
B : \(5^5 * 7^1\) => no of factors\((5+1)(1+1) = 12\)
in this case, A > B

Let A: \(7^4 * 5^2\) => no of factors \((4+1)(2+1) = 15\)
B: \(7^5 * 5^1\) => no of factors \((5+1)(1+1) = 12\)
in this case, A < B

Insuff => Answer (E)
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Is positive integer A greater than positive integer B? [#permalink]
I took statement two to mean that EVERY prime factor is B is in A.
Which means that if B is 4 (2*2), then A is AT LEAST (2*2) since it has EVERY prime factor of B.

This would make the answer C. I get that maybe that's not the lesson being taught in the question, but I'm sure other people read it that way as well.
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Re: Is positive integer A greater than positive integer B? [#permalink]
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Re: Is positive integer A greater than positive integer B? [#permalink]
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