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# It takes printer A 4 more minutes than printer B to print 40

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Manager
Joined: 13 Aug 2009
Posts: 148

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WE 1: 4 years in IT
It takes printer A 4 more minutes than printer B to print 40 [#permalink]

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15 Feb 2010, 00:21
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Difficulty:

65% (hard)

Question Stats:

64% (02:35) correct 36% (03:34) wrong based on 82 sessions

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It takes printer A 4 more minutes than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. How long will it take printer A to print 80 pages?

A. 12
B. 18
C. 20
D. 24
E. 30

OPEN DISCUSSION OF THIS QUESTION IS HERE: it-takes-printer-a-4-more-minutes-than-printer-b-to-print-98479.html
[Reveal] Spoiler: OA

Last edited by Bunuel on 29 Sep 2013, 09:26, edited 1 time in total.
Renamed the topic, edited the question and added the OA.

Kudos [?]: 327 [1], given: 7

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Re: work rate ps--plz solve [#permalink]

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15 Feb 2010, 06:03
1
KUDOS
working together A and B can finish typing 40 pages = (6/ 50) * 40 = 24/5 mints.

Per unit work done by A and B is individually denoted by 1/A and 1/(A - 4) respectively.

Now Substituting all in the form of an equation,we have

1/A + 1/(A -4) = 5 / 24

We obtain a quadratic equation as ,

5A^2 - 68A + 96 = 0

Solving this equation A = 12 mints. Hence for 80 pages 12 * 2 = 24 mints.

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Last edited by amit2k9 on 15 Feb 2010, 10:41, edited 1 time in total.

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Manager
Joined: 10 Jan 2010
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Location: Germany
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Re: work rate ps--plz solve [#permalink]

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15 Feb 2010, 08:42
50 pages = 6 mins
40 pages = (6/50)*40 = \frac{24}{5}mins
40 pages = a + b (but a = b + 4mins)

Since each printer can do 1/a or 1/b work per unit, we can solve the equation:

$$1/a + 1/(a-4)= 5/24$$

Solved - like amit2k9 did - with a quadratic equation:

$$5a^2 - 68a + 96 = 0$$

$$a^2 - 68a/5 + 96/5 = 0$$

$$(a-8/5)*(a-60/5) = 0$$

$$a = 8/5 or a = 12$$ --> only 12 works

Hence, a needs 12 mins for 40 pages --> 24 mins = 80 pages

Kudos [?]: 31 [0], given: 7

GMAT Instructor
Joined: 04 Jul 2006
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Kudos [?]: 341 [0], given: 0

Re: work rate ps--plz solve [#permalink]

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15 Feb 2010, 11:20
MSoS wrote:
50 pages = 6 mins
40 pages = (6/50)*40 = \frac{24}{5}mins
40 pages = a + b (but a = b + 4mins)

Since each printer can do 1/a or 1/b work per unit, we can solve the equation:

$$1/a + 1/(a-4)= 5/24$$

Solved - like amit2k9 did - with a quadratic equation:

$$5a^2 - 68a + 96 = 0$$

$$a^2 - 68a/5 + 96/5 = 0$$

$$(a-8/5)*(a-60/5) = 0$$

$$a = 8/5 or a = 12$$ --> only 12 works

Hence, a needs 12 mins for 40 pages --> 24 mins = 80 pages

If you hate factoring, you could reason that the LCM of a and a - 4 is 24 and thus suspect that a is 12

Kudos [?]: 341 [0], given: 0

Manager
Status: Getting ready for the internship summer
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Location: Rochester, NY
Schools: Simon
WE 1: JPM - Treasury
Re: work rate ps--plz solve [#permalink]

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15 Feb 2010, 16:41
If you don't want to deal with quadratics this question is a good choice to just pick numbers.

$$\frac{1}{x} + \frac{1}{x+4} = \frac{5}{24}$$

$$\frac{1}{12} + \frac{1}{8} = \frac{5}{24}$$

x = 12, so the answer is 24.

Kudos [?]: 31 [0], given: 23

Director
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Kudos [?]: 919 [0], given: 322

Concentration: General Management, General Management
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WE: Information Technology (Investment Banking)
Re: work rate ps--plz solve [#permalink]

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28 Sep 2013, 10:40
40/t + 40/(t+4) = 50/6

5t^2 -28t - 96 = 0

Substitute t=8 it satisfies

Hence time for 20 pages (t+4) =12
Time for 40 is 24

Hence (D) !
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Kudos [?]: 919 [0], given: 322

Math Expert
Joined: 02 Sep 2009
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Kudos [?]: 133146 [0], given: 12415

Re: It takes printer A 4 more minutes than printer B to print 40 [#permalink]

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29 Sep 2013, 09:26
Let the time needed to print 40 pages for printer A be $$a$$ minutes, so for printer B it would be $$a-4$$ minutes.

The rate of A would be $$rate=\frac{job}{time}=\frac{40}{a}$$ pages per minute and the rate of B $$rate=\frac{job}{time}=\frac{40}{a-4}$$ pages per minute.

Their combined rate would be $$\frac{40}{a}+\frac{40}{a-4}$$ pages per minute. Also as "two printers can print 50 pages in 6 minutes" then their combined rate is $$rate=\frac{job}{time}=\frac{50}{6}$$, so $$\frac{40}{a}+\frac{40}{a-4}=\frac{50}{6}$$.

$$\frac{40}{a}+\frac{40}{a-4}=\frac{50}{6}$$ --> $$\frac{1}{a}+\frac{1}{a-4}=\frac{5}{24}$$. At this point we can either try to substitute the values from answer choices or solve quadratic equation. Remember as we are asked to find time needed for printer A to print $$80$$ pages, then the answer would be $$2a$$ (as $$a$$ is the time needed to print $$40$$ pages). Answer D works: $$2a=24$$ --> $$a=12$$ --> $$\frac{1}{12}+\frac{1}{8}=\frac{5}{24}$$.

OPEN DISCUSSION OF THIS QUESTION IS HERE: it-takes-printer-a-4-more-minutes-than-printer-b-to-print-98479.html
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Kudos [?]: 133146 [0], given: 12415

Re: It takes printer A 4 more minutes than printer B to print 40   [#permalink] 29 Sep 2013, 09:26
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