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Re: M01-08 [#permalink]
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Since this is a PS question. shouldn't the answer choices be either ascending or descending?
Intern
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Re: M01-08 [#permalink]
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I think this is a high-quality question and I agree with explanation. A good question with a little trick to follow.
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Intern
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Re: M01-08 [#permalink]
I think this is a high-quality question and I agree with explanation. Fantastic solution. So simple!
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Re: M01-08 [#permalink]
Expert Reply
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re: M01-08 [#permalink]
How I solved it:

\(1^9^9^9\) = 1

When looking at the remaining values, notice that all of the exponents share a GCF: 50. Raise each of these remaining values to the \(\frac{1}{50}\) power

You're now left with \(2^6\), \(3^4\), \(4^2\), and \(16^1\). From here, it's really simple to find each of these values and realize the largest value is \(3^4\) = 81.
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Re M01-08 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re M01-08 [#permalink]
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