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I incorrectly selected A.
i thought that

X is an integer so X-1, X-2 and X-3 are 3 consecutive numbers and since product of 3 numbers is >0 so all 3 numbers should be either positive or any two can be -ve.

No any 2 can not be negative cause they are consecutive. if 2 are -ve and one is +ve then it would be -2, -1 and 0 but it is given that product can not be zero.
So we ultimately left with one solution of all 3 +ve no hence.
and if the 3 consecutive number less than X are positive then X will be greater than 3.

I got the way you solved it. I understood it before in one of your post but it did not striked in my mind when i was giving test. Can you plese tell me that what is the flaw in my thinking.
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him1985 wrote:
I incorrectly selected A.
i thought that

X is an integer so X-1, X-2 and X-3 are 3 consecutive numbers and since product of 3 numbers is >0 so all 3 numbers should be either positive or any two can be -ve.

No any 2 can not be negative cause they are consecutive. if 2 are -ve and one is +ve then it would be -2, -1 and 0 but it is given that product can not be zero.
So we ultimately left with one solution of all 3 +ve no hence.
and if the 3 consecutive number less than X are positive then X will be greater than 3.

I got the way you solved it. I understood it before in one of your post but it did not striked in my mind when i was giving test. Can you plese tell me that what is the flaw in my thinking.


You assumed (incorrectly) that x is an integer.
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Re: M03-01 [#permalink]
Hello Bunuel. Can you please explain the solution in a more lay terms...i implemented similar logic as him1985. If x<3 then the product of the three terms will be negative - isn't it? and we are given that the product of these three terms is +ve...so doesn't that imply that x>3? Can you please point out the flaw in my logic? Thanks for your help.
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I think this is a high-quality question and I agree with explanation. Hi, i used following logic to solve this question. Pls let me know whether my logic seems ok.

Statement 1 implies x-3>0, x-2>0 and x-1>0, and hence x>3, x>2 and x>1. So, x could be more than 3 and less than/equal to 3 (e.g 2,3). Not sufficient

Statement 2: x>1. Not sufficient

Combine: x could be 2, 3 or more than three. Not sufficient
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Re: M03-01 [#permalink]
hi Bunuel

if the question had said x is an integer, confirm A would have been suffient?
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streetking wrote:
hi Bunuel

if the question had said x is an integer, confirm A would have been suffient?


Yes. (1) gives 1 < x < 2 or x > 3. If x were an integer then x could be 4, 5, 6, ... and in the case we would have an YES answer to the question whether x > 3.
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My solution. I always prefer to analyze from statement 2. So,

(2) Clearly insufficient. x>1 does not mean that x>3. X could be either 2 (the answer is no) or 4 (the answer is yes)
(1) Clearly insufficient. Roots of the polynomial are 1, 2 and 3. Could be less or greater than 3 as well.

(2)+(1). If x>1, it means that (x-3)(x-2) must be both positive or negative. If x=1.5, then (x-3)(x-2)>0. But x is less than 3, so the answer is NO. If x=4, then (x-3)(x-2) also greater than 0. And x greater than 3, so the answer is YES.

Answer: E
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Re: M03-01 [#permalink]
I think this is a high-quality question and I agree with explanation.
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I think this is a high-quality question and I agree with explanation. tricky. I never even thought about fractions.
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From statement 1)

x cannot be 3 or 2 or 1 as it will be invalidate the statement.

Either all three are positive or two are negative.

If we take x = 3.1 then

(3.1 - 3) * (3.1 - 2) * (3.1 - 1) > 0 and the answer is yes x > 3

If we take x = 1.1

Then (1.1 - 3) * (1.1 - 2) * (1.1 - 1) > 0 and the answer is no. X is not > 3. So insufficient.

Moving to statement 2)

X > 1 this would mean x could be anything so insufficient.

Combining both we still could create the same scenario created while solving for statement 1.

The key point in solving this is not to assume that x must be an integer.

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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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