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M24-20

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Math Expert
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V
Joined: 02 Sep 2009
Posts: 58445
M24-20  [#permalink]

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New post 16 Sep 2014, 01:21
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

87% (01:01) correct 13% (00:42) wrong based on 68 sessions

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Math Expert
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V
Joined: 02 Sep 2009
Posts: 58445
Re M24-20  [#permalink]

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New post 16 Sep 2014, 01:21
Official Solution:

Which of the following fractions is the largest?

A. \(\frac{11}{27}\)
B. \(\frac{4}{9}\)
C. \(\frac{1}{3}\)
D. \(\frac{25}{81}\)
E. \(\frac{3}{20}\)


Obviously \(\frac{3}{20}\) is the smallest number. So, we should compare the remaining four. The lowest common denominator of these fractions is 81:

A. \(\frac{11}{27}= \frac{33}{81}\)

B. \(\frac{4}{9}= \frac{36}{81}\)

C. \(\frac{1}{3}= \frac{27}{81}\)

D. \(\frac{25}{81}= \frac{25}{81}\)

We can see that option B offers the largest number.


Answer: B
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GMAT 1: 640 Q48 V29
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Re: M24-20  [#permalink]

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New post 03 May 2018, 07:36
+1 for option B. Convert fractions to common denominator and compare. 4/9 has the highest value ! Hence option B
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Re: M24-20  [#permalink]

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New post 19 Feb 2019, 05:20
IMO very useful concept to learn

\(\frac{a}{b}\)>\(\frac{c}{d}\) if ad>cb

Example: Is \(\frac{4}{9}\)>\(\frac{3}{7}\) ?
4*7>9*3
Answer is YES

Regards
L
GMAT Club Bot
Re: M24-20   [#permalink] 19 Feb 2019, 05:20
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