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Re M2612
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16 Sep 2014, 01:25



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Re: M2612
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16 Sep 2014, 10:42
Bunuel wrote: Official Solution:
If \(3 \lt x \lt 5\) and \(7 \lt y \lt 9\), which of the following represents the range of all possible values of \(yx\)?
A. \(4 \lt yx \lt 4\) B. \(2 \lt yx \lt 4\) C. \(12 \lt yx \lt 4\) D. \(12 \lt yx \lt 12\) E. \(4 \lt yx \lt 12\)
To get max value of \(yx\) take max value of \(y\) and min value of \(x\): \(9(3)=12\); To get min value of \(yx\) take min value of \(y\) and max value of \(x\): \(7(5)=12\); Hence, the range of all possible values of \(yx\) is \(12 \lt yx \lt 12\).
Answer: D This question is good but it would be interesting to see a question with the same guidelines as to find the range of values but with the variables x/y or both with inclusive numbers like 3<=x<5 and 7<y<=9. Also if possible, kindly suggest similar problems.



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16 Sep 2014, 14:32
earnit wrote: Bunuel wrote: Official Solution:
If \(3 \lt x \lt 5\) and \(7 \lt y \lt 9\), which of the following represents the range of all possible values of \(yx\)?
A. \(4 \lt yx \lt 4\) B. \(2 \lt yx \lt 4\) C. \(12 \lt yx \lt 4\) D. \(12 \lt yx \lt 12\) E. \(4 \lt yx \lt 12\)
To get max value of \(yx\) take max value of \(y\) and min value of \(x\): \(9(3)=12\); To get min value of \(yx\) take min value of \(y\) and max value of \(x\): \(7(5)=12\); Hence, the range of all possible values of \(yx\) is \(12 \lt yx \lt 12\).
Answer: D This question is good but it would be interesting to see a question with the same guidelines as to find the range of values but with the variables x/y or both with inclusive numbers like 3<=x<5 and 7<y<=9. Also if possible, kindly suggest similar problems. Here is a similar questions with equal signs: if2x2and3y8whichofthefollowingrepresentsthe73539.html
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Hi another approach: sum up the 2 inequalities. but mind that the inequalities for such operaton should be looking the same way. since we need to find yx, we need to figure out how to transform the xinequality into the required form, i.e. x: 1. multiply by (1): we get +3>x>5 (remember to flip direction when * 1) 2. still is not looking the same way, therefore: 5<x<3 is just the same expression of the number line fragment 3. sumup: 7 < y <9 5 <x <3  75 < yx < 9+3 12 < yx< 12 ANSWER D
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Re M2612
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01 Jan 2016, 21:01
The questions states that the values are less than or greater than. but the answer explanation uses values that are greater than or EQUAL TO!! The explanation uses values that are not in the range of values given in the question



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Re: M2612
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03 Mar 2016, 17:35
The same for me.. Is the OE wrong? weiling476 wrote: The questions states that the values are less than or greater than. but the answer explanation uses values that are greater than or EQUAL TO!! The explanation uses values that are not in the range of values given in the question



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06 Apr 2016, 01:29
I don't agree with the explanation. If x is less than 9 then maximum value of x is 8. similarly for Y. kindly explain why maximum value for x is 9.



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Bunuel,
I'm not doubting the question itself, but when other people raised issues about the explanation, i think it's reasonable to doubt why the maximum VALUE of y is 9, and minimum VALUE of x is 3. Your wording is totally misguiding. You should say the maximum RANGE of y, rather than the value. The maximum value in this case is not 9, it's 8.99. Since the question is saying that the range is <>, not <=,>=.



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08 Jan 2017, 05:49
conneryeon001 wrote: Bunuel,
I'm not doubting the question itself, but when other people raised issues about the explanation, i think it's reasonable to doubt why the maximum VALUE of y is 9, and minimum VALUE of x is 3. Your wording is totally misguiding. You should say the maximum RANGE of y, rather than the value. The maximum value in this case is not 9, it's 8.99. Since the question is saying that the range is <>, not <=,>=. The question and the solution are absolutely correct. I think your doubt is addressed here: m26184451.html#p1655617Hope it helps.
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Re: M2612
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21 Apr 2017, 01:36
I think a much simpler way to solve this problem is to simply subtract two inequlities, according to the inequalities subtraction rules: (7<y<9)(5>x>3) <last inequality simply reversed. And we get the same answer 12<yx<12



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09 Nov 2017, 19:12
(1) 3<x<5 (2) 7<y<9
I made a mistake and subtracted (1) from (2) (since signs are similar in two statements) giving 4 < (yx) < 4
I agree with the OE but can someone explain if the above allowed and if yes what information does it convey?



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Re: M2612
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09 Nov 2017, 19:46
sevenplusplus wrote: (1) 3<x<5 (2) 7<y<9
I made a mistake and subtracted (1) from (2) (since signs are similar in two statements) giving 4 < (yx) < 4
I agree with the OE but can someone explain if the above allowed and if yes what information does it convey? No, it is wrong and you can simply test it with numbers.. (1) 3<x<5 ......let x be the lowest possible 2.99999 (2) 7<y<9 ...... let y be the MAX, so 8.99999 yx = 8.99999(2.99999) = 10 and 10 is not in the range 4<yx<4 you can ofcourse ADD the equations.. (1) 3<x<5 (2) 7<y<9 so 3+(7)<x+y<5+9......10<x+y<14 so to sum it all 1) if you are adding, take highest values and add them and for lower range add lowest values and add them 2) If you are subtracting, take highest of one and lowest of other
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Re: M2612
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11 Nov 2017, 11:17
chetan2u wrote: sevenplusplus wrote: (1) 3<x<5 (2) 7<y<9
I made a mistake and subtracted (1) from (2) (since signs are similar in two statements) giving 4 < (yx) < 4
I agree with the OE but can someone explain if the above allowed and if yes what information does it convey? No, it is wrong and you can simply test it with numbers.. (1) 3<x<5 ......let x be the lowest possible 2.99999 (2) 7<y<9 ...... let y be the MAX, so 8.99999 yx = 8.99999(2.99999) = 10 and 10 is not in the range 4<yx<4 you can ofcourse ADD the equations.. (1) 3<x<5 (2) 7<y<9 so 3+(7)<x+y<5+9......10<x+y<14 so to sum it all 1) if you are adding, take highest values and add them and for lower range add lowest values and add them 2) If you are subtracting, take highest of one and lowest of other Thanks a ton. Sent from my iPhone using GMAT Club Forum mobile app



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Re: M2612
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27 May 2018, 15:10
Bunuel wrote: If \(3 \lt x \lt 5\) and \(7 \lt y \lt 9\), which of the following represents the range of all possible values of \(yx\)?
A. \(4 \lt yx \lt 4\) B. \(2 \lt yx \lt 4\) C. \(12 \lt yx \lt 4\) D. \(12 \lt yx \lt 12\) E. \(4 \lt yx \lt 12\) Can be solved in less than 20 secs by looking at the answer choices. Since each answer choice has yx in the middle, we can directly compare the min and max values across the different answer choices. The range of choice D covers all of the other ranges. This means that if any choice besides D is correct, then D would also be correct, but we cant have 2 right answers, so answer is D.



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Re: M2612
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22 Jul 2018, 01:26
Bunuel, Hi Bunuel, Would you mind sharing an explanation by plotting on line, if possible? Thanks!










