Last visit was: 25 Apr 2026, 16:36 It is currently 25 Apr 2026, 16:36
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,830
Own Kudos:
Given Kudos: 105,886
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,830
Kudos: 811,281
 [36]
3
Kudos
Add Kudos
33
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,830
Own Kudos:
811,281
 [2]
Given Kudos: 105,886
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,830
Kudos: 811,281
 [2]
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
avatar
cyb
Joined: 17 Sep 2015
Last visit: 18 May 2021
Posts: 6
Own Kudos:
12
 [4]
Given Kudos: 8
GMAT 1: 760 Q50 V42
GPA: 3.65
Products:
GMAT 1: 760 Q50 V42
Posts: 6
Kudos: 12
 [4]
4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Own Kudos:
3,890
 [16]
Given Kudos: 816
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
GMAT 1: 750 Q49 V44
Posts: 2,319
Kudos: 3,890
 [16]
10
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
happyface101
iwantstanford
How did you know to split the -39 into 3 parts: -12, -18, and -9?

Hi Experts - can you please clarify how to recognize that we need to split -39 to solve?

I'm not sure how to recognize that this is the approach. Also, how do you know what to split -39 into?

The trick with these questions that ask you about max/min of a second degree polynomial is that you will invariably get a value of the form (a\(\pm\)b) wherein, the minimum value of any square = 0. Thus try to create perfect squares out of the given polynomials.


Realize that \((a\pm b)^2 = a^2 \pm 2*a*b + b^2\).

Given expression: \(−3x^2+12x−2y^2−12y−39\) ---> try to create perfect squares :

\((-3x^2+12x) + (-2y^2-12y)-39 ---> -3 (x^2-4x) -2 (y^2+6y) -39 ----> 3 (x^2-4x+4-4) -2 (y^2+6y+9-9) -39\)


---> \(3 (x^2-4x+4-4) -2 (y^2+6y+9-9) -39\) ---> \(-3[(x-2)^2-4] -2 [(y+3)^2-9]-39\) ----> \(-3(x-2)^2+12 -2(y+3)^2+18-39\)

----> \(-3(x-2)^2+12 -2(y+3)^2+18-39\) --->\(-3(x-2)^2-2(y+3)^2-9\)

As mentioned above, the minimum value of a perfect square = 0 --> to maximize the given expression,

you need to put \((x-2)^2 =0\) and\((y+3)^2=0\) ---> giving you 0+0-9=-9 as the maximum value.

Any other values of\((x-3)^2\) and \((y+3)^2\)will give you a smaller negative value hence 'minimizing' instead of maximizing the expression.

Hope this helps.
avatar
GMChand
Joined: 01 Sep 2018
Last visit: 24 Nov 2018
Posts: 1
Own Kudos:
33
 [33]
Location: India
GPA: 4
WE:Engineering (Manufacturing)
Posts: 1
Kudos: 33
 [33]
23
Kudos
Add Kudos
10
Bookmarks
Bookmark this Post
If you are familiar with basic differentiation, it would be very quick.

Solution: Let the given equation be 1.

Step 1.Find differentiation of equ 1 wr.to "X" and equate to "0" (This is the standard rule for a differentiation in order to get maximum value)
Hence, -6x+12=0
therefore x=2

Step 2.Then differentiate the equ 1 wr.to "Y" and equate to "0"
-4y-12=0
therefore y=-3

Step 3.Submit both x=2 and y=-3 in the equ. 1 to get the maximum value.
Therefore the answer is -9.

Differentiation approach can save lot of time while determining the maximum value of an expression.
User avatar
HasnainAfxal
Joined: 06 Sep 2018
Last visit: 12 Mar 2022
Posts: 125
Own Kudos:
65
 [2]
Given Kudos: 72
Location: Pakistan
Concentration: Finance, Operations
GPA: 2.87
WE:Engineering (Other)
Products:
Posts: 125
Kudos: 65
 [2]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
i solved this question in following way:
to maximize this expression, we need to maximize terms containing 'x', i.e
\(−3x^2+12x\)
and we need to maximize terms containing 'y', i.e
\(−2y^2−12y\)
So,
\(−3x^2+12x\) will be maximum when x is positive and \(x=2\).
\(−2y^2−12y\) will be maximum when y is negative and \(y=-3\)
so by plugging in \(x=2\) and \(y=-3\) in given expression we get \(-9\) and that's the maximum value we can get from this expression.
User avatar
ari.banerjee
Joined: 31 Mar 2017
Last visit: 03 Oct 2020
Posts: 132
Own Kudos:
136
 [4]
Given Kudos: 174
Location: Canada
Concentration: Strategy, Finance
GMAT 1: 560 Q44 V24
GMAT 2: 540 Q31 V34
GMAT 3: 590 Q36 V34
GMAT 4: 600 Q42 V30
GRE 1: Q159 V152
GPA: 4
GMAT 4: 600 Q42 V30
GRE 1: Q159 V152
Posts: 132
Kudos: 136
 [4]
3
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Not sure if this approach helps but I kinda took the differential approach and found the answer in a minute...

d/dx(expression)= 0 to find the value of x and d/dy(expression)=0 to find the value of y. This is the way we determine maximas in differentiation. This is a basic second order differential and anyone who has been through grade 12 in science/Math/Physics should be able to solve this.

d/dx=-6x+12=0, x=2

Similarly, d/dy= -4y-12=0, y=-3,

Sub x and y in the equation and you get maximum value of the expression as -9.

Hope this helps and please give me a kudos if you relate to the approach!
avatar
TheModo
Joined: 10 Apr 2020
Last visit: 15 Jun 2021
Posts: 16
Own Kudos:
13
 [4]
Given Kudos: 312
Location: United States
Posts: 16
Kudos: 13
 [4]
2
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
I found out why [b]Bunuel breaks out the "-39", and have found a formula to find the maximum of a second degree polynomial. A detailed understanding and step-by-step walkthrough is included below.[/b]

Disclaimer: This post is "wordy"; however, as any of us have likely determined throughout our studying, understanding the entire thought process, or logic, of how to arrive at a given answer is important. :)

Logic
The key to this question is to recognize exactly what it is testing, which is: "how do you find the maximum of a second degree polynomial?"

Upon recognizing this "task" that the question is testing, deciphering Bunuel's logic of breaking out the "-39" to multiple terms makes complete sense.

As background, to find the maximum of a second degree polynomial (ax^2 + bx + c), the formula is: "(c - ((b^2) / (4a)))". More on that here: https://study.com/academy/lesson/find-the-maximum-value-of-a-function-lesson-practice-quiz.html. As a further note of background, if the 'a-coefficient' is positive, the polynomial will have a minimum, and if the 'a-coefficient' is negative, the polynomial will have a maximum. Regardless, the formula you use to find either maximum or minimum is the exact same: (c - ((b^2) / (4a))).

Upon recognizing what the test is asking/testing, and knowing the formula stated above to find the maximum of a second degree polynomial, you can see why Bunuel breaks out the "-39" to create two separate second degree polynomials; as a way to create two polynomials that you can then find the respective maximum values for.

Step-by-step
1.) -3x^2 + 12x - 2y^2 - 12y - 39 --> you should be able to recognize that there is a "complete" 2nd degree polynomial in "-2y^2 - 12y - 39"; however, the "-3x^2 + 12x" is "incomplete" as there is no "c" value.
2.) At this point, you need to ask yourself, "How can I make two complete 2nd degree polynomials?" Specifically, how can you write "-3x^2 + 12x +/- R" and "-2y^2 - 12y +/- S"?, R and S would be derived from -39.
Note: "R" and "S" are term names that I made up to help distinguish in this post between the respective polynomials, as opposed to simply calling them both "c", which is technically their term name for a polynomial.
2a.) To find values for R and S, you need to ask yourself, "what two numbers that add up to -39 (either completely or with values left over) can I use that would 'complete' X's and Y's respective polynomials, and result in each polynomial to have the a-coefficient factored out?" For example, the "R" (or "c") value of the "-3x^2 + 12 +/- R" polynomial would have to be divisible by 3, since "-3" is the a-coefficient, in order to create ease of factoring. Similarly, the "S" (or "c") value of the "-2y^2 - 12y +/- S" polynomial would have to be divisible by 2, for the exact same reason.
2b.) If you're following up to this point, there are multiple ways to break out "-39" to be numbers that would "complete" each polynomial (e.g., (-12)+(-18)+(-9)=-39; (-3)+(-3)+(-33)=-39; etc.). Essentially, any of these numbers will work to aid you in arriving at the answer, just remember that the R and S terms should be divisible by their respective a-coefficient.
3.) For the sake of showing why/how Bunuel broke out -39 to -12, -18, and -9, we will do that here.
3a.) The new formula from the prompt is: -3x^2 + 12x - 12 - 2y^2 - 12y - 18 - 9 --> Do you see how you now have two "complete" polynomials" for X and Y with -9 left over?
3b.) Mark the polynomials with parentheses to distinguish between them... (-3x^2 + 12x - 12) + (-2y^2 - 12y - 18) - 9
Steps 4 and 5 are "new" compared to the previous posts I have seen on this question.
4.) Remember how I mentioned above how to find the maximum of a polynomial (c - ((b^2) / 4a)? Use this formula to find the maximum value for each newly created "complete" polynomial
4a.) For the X-polynomial, the maximum formula becomes: (-12 - ((12^2) / 4(-3))) --> (-12 - ((144) / (-12))) --> (-12 - (-12)) --> (-12 + 12) --> 0... the maximum value for the X-polynomial is "0"... hold on to that thought
4b.) For the Y-polynomial, the maximum formula becomes: (-18 - ((-12^2) / 4(-2))) --> (-18 - ((144) / (-8))) --> (-18 - (-18)) --> (-18 + 18) --> 0... the maximum value for the Y-polynomial is "0"... again, hold on to that though; we aren't done!
5.) Now, combine all of the new numbers. The new equation finally breaks down to: 0 + 0 - 9... which finally results in: -9 (answer B).

As always, please feel free to share thoughts, questions, comments, and/or concerns. As you can likely understand, this question threw me for a while, and I did not understand Bunuel's logic of breaking out the "-39", thus I researched how to find the max of a second degree polynomial, did not see the affiliated logic shared throughout the thread, and felt compelled to share. Hope this helps!
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,830
Own Kudos:
Given Kudos: 105,886
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,830
Kudos: 811,281
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
User avatar
BottomJee
User avatar
Retired Moderator
Joined: 05 May 2019
Last visit: 09 Jun 2025
Posts: 994
Own Kudos:
Given Kudos: 1,009
Affiliations: GMAT Club
Location: India
GMAT Focus 1: 645 Q82 V81 DI82
GMAT 1: 430 Q31 V19
GMAT 2: 570 Q44 V25
GMAT 3: 660 Q48 V33
GPA: 3.26
WE:Engineering (Manufacturing)
Products:
GMAT Focus 1: 645 Q82 V81 DI82
GMAT 3: 660 Q48 V33
Posts: 994
Kudos: 1,459
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think this is a high-quality question and I agree with explanation.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,986
Own Kudos:
Posts: 38,986
Kudos: 1,118
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109830 posts
Founder
43156 posts