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Math Revolution Daily quiz (Day 25) [#permalink ]

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02 Dec 2016, 01:24
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Math Revolution Daily quiz (Day 26) [#permalink ]

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05 Dec 2016, 01:03
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Math Revolution Daily quiz (Day 27) [#permalink ]

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06 Dec 2016, 01:37
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Re: Math Revolution Daily quiz (Day 27) [#permalink ]

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06 Dec 2016, 01:51

1) Solving the inequality gives us \(x \in (-1;0) u (0;1)\). Option 1 and Option 2 include both the solutions and non-solutions, making them insufficient. Combination of (1) and (2) give us the exact interval, where the inequality holds. C it is.

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Math Revolution Daily quiz (Day 29) [#permalink ]

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08 Dec 2016, 01:32
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Math Revolution Daily quiz (Day 30) [#permalink ]

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09 Dec 2016, 01:37
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Math Revolution Daily quiz (Day 31) [#permalink ]

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12 Dec 2016, 01:08
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Math Revolution Daily quiz (Day 32) [#permalink ]

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13 Dec 2016, 01:20
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Math Revolution Daily quiz (Day 33) [#permalink ]

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14 Dec 2016, 01:08
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Math Revolution Daily quiz (Day 34) [#permalink ]

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15 Dec 2016, 01:09
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Math Revolution Daily quiz (Day 35) [#permalink ]

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16 Dec 2016, 03:24
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Math Revolution Daily quiz (Day 36) [#permalink ]

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19 Dec 2016, 00:24
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Math Revolution Daily quiz (Day 37) [#permalink ]

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20 Dec 2016, 01:33
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Math Revolution Daily quiz (Day 38) [#permalink ]

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21 Dec 2016, 01:39
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Math Revolution Daily quiz (Day 39) [#permalink ]

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22 Dec 2016, 00:47
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Re: Math Revolution Daily quiz (Day 37) [#permalink ]

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22 Dec 2016, 08:57

MathRevolution wrote:

Math Revolution Daily quiz (Day 37)Just spare 15 minutes to study each day, and you will be amazed by significant improvement in GMAT Math! “If you like this question, consider subscribing to our 15 minutes a Day Daily Quiz" Receive "Up-To-Date" 5 math questions and solutions everyday through e-mailhttp://mathrevolution.com/gmat/daily_quiz My approach got me the answers as "either statement alone" i.e. "D"

From stat 1) n/8 = ax+3, implying n = 8ax + 24, implying n/6 = 3/2 (ax) + 4, 3/2 (ax) shall always give 1 as remainder therefore total remainder = 5...Suff.

From stat 2) (n-1)/9 = ax+8, implies n-1 = 9ax + 72, implies (n-1)/6 = 3/2(ax) + 12, 3/2 (ax) shall always give 1 as remainder whereas 12 is divisible terefore remiander = 1...suff

Therefore "D"

where did I go wrong:(

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Math Revolution Daily quiz (Day 40) [#permalink ]

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23 Dec 2016, 00:48
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Re: Math Revolution Daily quiz (Day 37) [#permalink ]

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25 Dec 2016, 18:17
saurabhsavant Hello,

In fact, "n/8 = ax+3,(n-1)/9 = ax+8" is incorrect. It is supposed to be shown as "n=8p+3 and n-1=9q+8".

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Re: Math Revolution Daily quiz (Day 37) [#permalink ]

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27 Dec 2016, 11:05

MathRevolution wrote:

saurabhsavant Hello,

In fact, "n/8 = ax+3,(n-1)/9 = ax+8" is incorrect. It is supposed to be shown as "n=8p+3 and n-1=9q+8".

Aaarrgghhh...what a stupid mistake, thanx a ton for making it clear.

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Re: Math Revolution Daily quiz (Day 37) [#permalink ]

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10 Jan 2017, 23:01
saurabhsavant wrote:

MathRevolution wrote:

Math Revolution Daily quiz (Day 37)Just spare 15 minutes to study each day, and you will be amazed by significant improvement in GMAT Math! “If you like this question, consider subscribing to our 15 minutes a Day Daily Quiz" Receive "Up-To-Date" 5 math questions and solutions everyday through e-mailhttp://mathrevolution.com/gmat/daily_quiz My approach got me the answers as "either statement alone" i.e. "D"

From stat 1) n/8 = ax+3, implying n = 8ax + 24, implying n/6 = 3/2 (ax) + 4, 3/2 (ax) shall always give 1 as remainder therefore total remainder = 5...Suff.

From stat 2) (n-1)/9 = ax+8, implies n-1 = 9ax + 72, implies (n-1)/6 = 3/2(ax) + 12, 3/2 (ax) shall always give 1 as remainder whereas 12 is divisible terefore remiander = 1...suff

Therefore "D"

where did I go wrong:(

Hi saurabhsavant,

Condition 1)

You shouldn't write n/8 = ax + 3 and so n = 8ax + 24 = 8(ax + 3).

It doesn't mean that its remainder is 3 when n is divided by 8, but it means n is multiple of 8.

It should be expressed by n = 8a + 3

Condition 2)

You shouldn't write (n-1)/9 = ax + 8. It means n - 1 = 9 * ( ax + 8 ) and the remainder of n - 1 is 0 when n - 1 is divided by 9

It should be expressed by n - 1 = 9b + 8

Happy Studying!

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Re: Math Revolution Daily quiz (Day 37)
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