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Math Revolution Daily quizzes

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Math Revolution Daily quizzes [#permalink]

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New post 31 Oct 2016, 02:29
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Math Revolution Daily Quiz (Day 1)

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New post 31 Oct 2016, 20:15
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Math Revolution Daily Quiz (Day 1)

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Is s+t/2=5p/2------->is s+t=5p??

(1) s+t+p/3=2p (as s<p<t median=p)

or s+t+p=6p------s+t=5p-------->suff

(2) s+t=5p------.directly gives ans.------>suff

Ans D

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Math Revolution Daily quiz (Day 2) [#permalink]

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Re: Math Revolution Daily quiz (Day 2) [#permalink]

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New post 02 Nov 2016, 04:34
Let the two digit number be ab
10a+b = 4(a+b)
6a = 3b
2a = b
Possible values of (b,a) include :(2,1), (4,2), (6,3) & (8,4)

(1) tens digit is 1
a = 1 => b =2
number is 12

(2) units value is a prime number.
from the possible values, only b=2 satisfies.
so a=1
number is 12.

Either of the options is sufficient. Option D

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Math Revolution Daily quiz (Day 4)

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Math Revolution Daily quiz (Day 7) [#permalink]

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Math Revolution Daily quiz (Day 7)

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Math Revolution Daily quiz (Day 8) [#permalink]

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Math Revolution Daily quiz (Day 10)

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Re: Math Revolution Daily quiz (Day 12) [#permalink]

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New post 15 Nov 2016, 11:51
S1 - n=4p+odd integer, where p is any integer
i.e. remainder can be 1,3 which are odd.
any number with remainder 1,3 when divided by 4 , gives remainder 1 when divided by 2, which can be checked by substituting some values.
Hence sufficient.

S2 - n=3q+odd integer, where q is any integer
i.e. remainder can be 1 which is only odd remainder.
any number when divided by 3 and leaving remainder 1 can have remainder 0 or 1 when divided by 2, hence not sufficient.

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Math Revolution Daily quiz (Day 13)

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Math Revolution Daily quiz (Day 14) [#permalink]

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Math Revolution Daily quiz (Day 14)

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Math Revolution Daily quiz (Day 15) [#permalink]

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Math Revolution Daily quiz (Day 15)

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Re: Math Revolution Daily quiz (Day 15) [#permalink]

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New post 18 Nov 2016, 13:17
FROM STATEMENT - I ( Insufficient)

\(3^{x + y} = 3^4\)

Or, \(x + y = 4\)

FROM STATEMENT - II ( Insufficient)

\(3^{x + 2y} = 3^3\)

Or,\(x + 2y = 3\)

FROM STATEMENT - I & II ( Sufficient)

\(x + y = 4\) or \(2x + 2y = 8\)
\(x + 2y = 3\)

Now, \(x + 2y = 3\)

Or, \(2y = 3 - x\)

Or, 8 - 2x = 3 - x

Or, x = 5 So y = -1

Thus BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked, answer will be (C)
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Math Revolution Daily quiz (Day 16)

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Math Revolution Daily quiz (Day 17)

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Math Revolution Daily quiz (Day 20) [#permalink]

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Math Revolution Daily quiz (Day 20)

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Re: Math Revolution Daily quiz (Day 20) [#permalink]

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New post 25 Nov 2016, 03:19
If the least and the average salary are same, then all the entries are same. Therefore, median =$95K

So, it's C

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Math Revolution Daily quiz (Day 24) [#permalink]

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Math Revolution Daily quiz (Day 24)

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Math Revolution Daily quiz (Day 24)   [#permalink] 01 Dec 2016, 01:13

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