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Math Revolution Daily quizzes [#permalink ]

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31 Oct 2016, 02:29
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Re: Math Revolution Daily quizzes [#permalink ]

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31 Oct 2016, 20:15

MathRevolution wrote:

Math Revolution Daily Quiz (Day 1)Just spare 15 minutes to study each day, and you will be amazed by significant improvement in GMAT Math! “If you like this question, consider subscribing to our 15 minutes a Day Daily Quiz" Receive "Up-To-Date" 5 math questions and solutions everyday through e-mail http://mathrevolution.com/gmat/daily_quiz Is s+t/2=5p/2------->is s+t=5p??

(1) s+t+p/3=2p (as s<p<t median=p)

or s+t+p=6p------s+t=5p-------->suff

(2) s+t=5p------.directly gives ans.------>suff

Ans D

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Math Revolution Daily quiz (Day 2) [#permalink ]

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01 Nov 2016, 02:10
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Re: Math Revolution Daily quiz (Day 2) [#permalink ]

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02 Nov 2016, 04:34

Let the two digit number be ab

10a+b = 4(a+b)

6a = 3b

2a = b

Possible values of (b,a) include

2,1), (4,2), (6,3) & (8,4)

(1) tens digit is 1

a = 1 => b =2

number is 12

(2) units value is a prime number.

from the possible values, only b=2 satisfies.

so a=1

number is 12.

Either of the options is sufficient. Option D

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Math Revolution Daily quiz (Day 4) [#permalink ]

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03 Nov 2016, 01:37
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Math Revolution Daily quiz (Day 7) [#permalink ]

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08 Nov 2016, 02:12
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Math Revolution Daily quiz (Day 8) [#permalink ]

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09 Nov 2016, 01:32
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Math Revolution Daily quiz (Day 10) [#permalink ]

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11 Nov 2016, 01:02
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Math Revolution Daily quiz (Day 12) [#permalink ]

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15 Nov 2016, 02:04
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Re: Math Revolution Daily quiz (Day 12) [#permalink ]

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15 Nov 2016, 11:51

S1 - n=4p+odd integer, where p is any integer

i.e. remainder can be 1,3 which are odd.

any number with remainder 1,3 when divided by 4 , gives remainder 1 when divided by 2, which can be checked by substituting some values.

Hence sufficient.

S2 - n=3q+odd integer, where q is any integer

i.e. remainder can be 1 which is only odd remainder.

any number when divided by 3 and leaving remainder 1 can have remainder 0 or 1 when divided by 2, hence not sufficient.

Hence answer A.

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Math Revolution Daily quiz (Day 13) [#permalink ]

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16 Nov 2016, 01:13
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Math Revolution Daily quiz (Day 14) [#permalink ]

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17 Nov 2016, 04:08
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Math Revolution Daily quiz (Day 15) [#permalink ]

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18 Nov 2016, 01:18
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Re: Math Revolution Daily quiz (Day 15) [#permalink ]

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18 Nov 2016, 13:17

FROM STATEMENT - I ( Insufficient) \(3^{x + y} = 3^4\)

Or, \(x + y = 4\)

FROM STATEMENT - II ( Insufficient) \(3^{x + 2y} = 3^3\)

Or,\(x + 2y = 3\)

FROM STATEMENT - I & II ( Sufficient) \(x + y = 4\) or \(2x + 2y = 8\)

\(x + 2y = 3\)

Now, \(x + 2y = 3\)

Or, \(2y = 3 - x\)

Or, 8 - 2x = 3 - x

Or, x = 5 So y = -1

Thus BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked, answer will be (C)
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Math Revolution Daily quiz (Day 16) [#permalink ]

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21 Nov 2016, 01:53
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Math Revolution Daily quiz (Day 17) [#permalink ]

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22 Nov 2016, 01:35
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Math Revolution Daily quiz (Day 20) [#permalink ]

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25 Nov 2016, 02:06
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Re: Math Revolution Daily quiz (Day 20) [#permalink ]

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25 Nov 2016, 03:19

If the least and the average salary are same, then all the entries are same. Therefore, median =$95K

So, it's C

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Math Revolution Daily quiz (Day 23) [#permalink ]

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30 Nov 2016, 01:16
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Math Revolution Daily quiz (Day 24) [#permalink ]

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01 Dec 2016, 01:13
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Math Revolution Daily quiz (Day 24)
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