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Re: N=abc, N is a three digit number with hundreds digit a, tens digit b [#permalink]
Dare Devil wrote:
N=abc, N is a three digit number with hundreds digit a, tens digit b and units digit c. If a+b+c=20, what is the value of b?

(1) The product of digits a and c is 18.
a*c = 18
a,b,c are single digits
18 = 6*3 OR 9*2
if a = 6 and c= 3 then from a+b+c = 20, b = 11, which is not a single digit
So (6,3) is not possible
only possible solution is 9,2 for a,c
We are least bothered about the value of a, c as required value is b
a+b+c = 20
9+2+b = 30
b = 9
Sufficient

(2) b/c=1 and b<a
Since b,c are equal, their sum will be even (even if b=c = odd OR even)
As Even + even = even
odd + odd = even
possibilities of a is only even, as 2*a + b = 20 an even number
Since 10 is 2 digit number, and b < a, lets consider a =8, let b = c = x
8 + 2(x) = 20
b = c = x = 6

Next a = 6 (only even's possible from above explanation)
6 + 2(x) = 20
b= c = x = 7
b > a which is a contradiction, So a can only take 8, and in turn b,c can only be 6
So, b = 6
Sufficient

Option D is correct



From 2 options we are getting two different values for B..is it right approach?
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Re: N=abc, N is a three digit number with hundreds digit a, tens digit b [#permalink]
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PKGMAT wrote:
From 2 options we are getting two different values for B..is it right approach?

I have made the following observation in my previous post:

Obs.: in official questions, when the correct alternative choice is (D), we expect the unique answers (obtained in each statement alone) to be equal.

Reason for the observation: it was not the case here.

Regards,
Fabio.
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Re: N=abc, N is a three digit number with hundreds digit a, tens digit b [#permalink]
Give 100a+10b+c = 20 , to find 10b ?

Statement 1 : (a)*(c)=18, hence none of them is zero.
Possible Values :
2*9 = 18 ---> B can be 9 since a + b + c = 20
9*2 = 18---> B can be 9 since a + b + c = 20

Ruled out options : - (Since range of values for any figure can lie between 0 and 9 )
3*6 = 18---> B can be 11 since a + b + c = 20
6*3 = 18---> B can be 11 since a + b + c = 20

Hence statement 1 is alone sufficient. (B=9)

Statement 2: -
Give B/C =1 implies B=C additionally, its given b<a
From the above information we can infer that,
possible values of A , B , C can be
A + B + C =20
9 5.5 5.5
8 6 6
7 6.5 6.5
6 7 7
abc have to be an integer and given that a > b
Hence only possible option ---> a = 8 and B & C 6 .
Alone Sufficient

Hence, answer "D"
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Re: N=abc, N is a three digit number with hundreds digit a, tens digit b [#permalink]
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Re: N=abc, N is a three digit number with hundreds digit a, tens digit b [#permalink]
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