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Nicky and Cristina are running a 1,000 meter race. Since

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Nicky and Cristina are running a 1,000 meter race. Since  [#permalink]

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New post Updated on: 09 Sep 2012, 04:05
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Nicky and Cristina are running a 1,000 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?

(A) 15 seconds
(B) 18 seconds
(C) 25 seconds
(D) 30 seconds
(E) 45 seconds

Originally posted by siddhans on 06 Sep 2011, 23:59.
Last edited by Bunuel on 09 Sep 2012, 04:05, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Nicky and Cristina  [#permalink]

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New post 07 Sep 2011, 02:05
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The distance traveled by both of them is the same at the time of overtaking.

3(t+12) = 5t

t=18.

Cristina will catch up Nicky in 18 seconds.

So in 18 seconds Cristina would cover = 18*5 = 90 meter.

Now Time taken my Nicky to cover 90 meter = 90/3 = 30 Seconds.


Hope this helps!
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Re: Nicky and Cristina  [#permalink]

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New post 07 Sep 2011, 00:09
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ok.. im surprised by the answer...

nicky gets a headstart of 12 seconds.. and in this thime she runs 36 mts (12 * 3)
and by the time christina starts, the gap between them is 36 mts

since christina is faster than nicky by 2 m/s she reduces the gap by 2 m/s

and therefore the whole gap is covered in 18 seconds... but the question is how much time nicky would have run before christina catches up

18 + 12 (the headstart nicky got) = 30

so i think the answer's got to be 30 or the question should be modified to not include the head start time

am i missing something?
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Re: Nicky and Cristina  [#permalink]

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New post 07 Sep 2011, 01:40
Wat's the confusion here?
You are getting the correct ans, same as the OA..
Christina, being faster, runs for 18 secs. Nicki, runs for 30 secs..
ans is 30 secs..
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Re: Nicky and Cristina  [#permalink]

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New post 07 Sep 2011, 07:17
krishnasty wrote:
Wat's the confusion here?
You are getting the correct ans, same as the OA..
Christina, being faster, runs for 18 secs. Nicki, runs for 30 secs..
ans is 30 secs..



ok.. the OA was changed.... when i first attepmted the problem, the OA was 18 sec :-)
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Re: Nicky and Cristina  [#permalink]

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New post 09 Sep 2012, 02:58
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these questions are very easy to answer once they are logically understood.
see Nicky rate of running is 3 meter/sec and he has 12 second head start. so after 12 seconds he has run 36 meters "(3)(12)". now the question tell us that Cristina runs at a pace of 5 meters per second. she is running 2 meter/second faster than nicky (5-3=2). simply divide the 36 meters with 2 you will get the answer. 36/2= 18 seconds.
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Re: Nicky and Cristina  [#permalink]

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New post 09 Sep 2012, 04:49
sananoor wrote:
these questions are very easy to answer once they are logically understood.
see Nicky rate of running is 3 meter/sec and he has 12 second head start. so after 12 seconds he has run 36 meters "(3)(12)". now the question tell us that Cristina runs at a pace of 5 meters per second. she is running 2 meter/second faster than nicky (5-3=2). simply divide the 36 meters with 2 you will get the answer. 36/2= 18 seconds.



Here, your answer 18 seconds is the time taken by Cristina.
As Nicky has started 12 seconds early, total time taken by Nicky is 12+18 = 30 Seconds.
So, the answer is D.
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Re: Nicky and Cristina are running a 1,000 meter race. Since  [#permalink]

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New post 09 Sep 2012, 04:58
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Exactly the answer is 30 by adding 18 and 12...i just mentioned that i am placing the logic behind this question to find that 18...thanks by the way...
the other way one can do this question is
Nicky: (RT= D)---- his rate is 3 meter/second and time= t+12sec therefore the distance he covered will be 3(t+12)----------1
Christina: (RT=D)----- her rate is 5 meter/second and time = t therefore the distance she covered will be 5t---------------2

relating two distances
3(t+12) = 5t
t = 18

putting the value of t for nicky t+12 = 18 + 12= 30 and thats the answer
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Re: Nicky and Cristina are running a 1,000 meter race. Since  [#permalink]

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New post 01 Jun 2015, 22:41
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In speed and distance questions drawing a diagram helps in visualizing the problem and easy formulation of the equation.

Given Info
We are given that Nicky runs at a speed of 3 meters/second for 12 seconds before Cristina starts running at a speed of 5 meters/second. We are asked to find the time for which Nicky has run before Cristina catches up with him.

Approach
We know that Distance = Speed * Time. Since we know the speed at which Nicky runs and his head start time we can calculate his head start distance. We also know the speed at which Cristina runs. Once Cristina starts running, they both will run for the same time before Cristina catches up with Nicky.

Since we know the running speeds of both Nicky and Cristina, we can calculate their distance covered in terms of a common variable i.e. the time taken. As Nicky had a headstart, the extra distance covered by Cristina will be equal to the head start distance which Nicky had.

Working Out
Refer the below diagram

Image

Head start time given to Nicky = 12 seconds
Speed at which Nicky runs = 3 meters/second

Distance covered by Nicky = 12 * 3 = 36 meters

Let the time taken by Cristina to catch up with Nicky be t.
Speed at which Cristina runs = 5 meters/second

Distance covered by Cristina in time t = 5t
Distance covered by Nicky in time t = 3t

Since distance covered by Cristina in time t is 36 meters more than that covered by Nicky in time t, we can write

5t = 3t + 36 i.e. t = 18 seconds.

This is the time taken by Cristina to catch up with Nick. Since we are asked to find the time taken by Nicky, we will add the 12 seconds head start he had. So time for which Nicky ran before Cristina caught up with him = 18 + 12 = 30 seconds.

Hope this helps :)

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Re: Nicky and Cristina are running a 1,000 meter race. Since  [#permalink]

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New post 27 Jul 2017, 13:07
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siddhans wrote:
Nicky and Cristina are running a 1,000 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?

(A) 15 seconds
(B) 18 seconds
(C) 25 seconds
(D) 30 seconds
(E) 45 seconds


I guess the total distance is irrelevant here.

Relative Speed is 5 - 3 = 2 mps.

Distance traveled by Cristina in 12 seconds is 36 meters.

So, Nicky will have to catch up 12 * 3 = 36 meters at a speed of 2 mps.

Nicky will catch up in 18 sec.

Christina would have traveled 18 + 12 = 30 seconds.
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Re: Nicky and Cristina are running a 1,000 meter race. Since  [#permalink]

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New post 27 Jul 2017, 13:08
siddhans wrote:
Nicky and Cristina are running a 1,000 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?

(A) 15 seconds
(B) 18 seconds
(C) 25 seconds
(D) 30 seconds
(E) 45 seconds


I guess the total distance is irrelevant here.

Relative Speed is 5 - 3 = 2 mps.

Distance traveled by Cristina in 12 seconds is 36 meters.

So, Nicky will have to catch up 12 * 3 = 36 meters at a speed of 2 mps.

Nicky will catch up in 18 sec.

Christina would have traveled 18 + 12 = 30 seconds.
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Nicky and Cristina are running a 1,000 meter race. Since  [#permalink]

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New post 14 Dec 2019, 07:55
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siddhans wrote:
Nicky and Cristina are running a 1,000 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?

(A) 15 seconds
(B) 18 seconds
(C) 25 seconds
(D) 30 seconds
(E) 45 seconds


GIVEN: Nicki is given a 12-second head start
Nicky runs at a pace of 3 meters per second
distance = (speed)(time)
Plug in values to get: distance = (3 meters per second)(12 seconds) = 36 meters
Nicki's head start = 36 meters

At this point the question becomes a shrinking gap question
(5 meters per second) - (3 meters per second) = 2 meters per second
So the gap shrinks at a rate of 2 meters per second

So we want to find the time it takes the gap to shrink from 36 meters to 0 meters
That is, the gap shrinks a total of 36 meters, at a rate of 2 meters per second

Time = Distance/Speed
Time = 36/2 = 18 seconds

How many seconds will Nicky have run before Cristina catches up to him?
IMPORTANT: Since we want to find Nicky's TOTAL running time, we must also include the 12 seconds he ran during his head start.

TOTAL running time = 18 seconds + 12 seconds = 30 seconds


Answer: D

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Re: Nicky and Cristina are running a 1,000 meter race. Since  [#permalink]

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New post 01 Jan 2020, 19:38
siddhans wrote:
Nicky and Cristina are running a 1,000 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?

(A) 15 seconds
(B) 18 seconds
(C) 25 seconds
(D) 30 seconds
(E) 45 seconds


Let’s let t = the time in seconds that Christina runs until catching up to Nicky. We can create the equation:

3(12 + t) = 5t

36 + 3t = 5t

36 = 2t

18 = t

Including the 12-second head start, Nicky has run 18 + 12 = 30 seconds before Cristina catches up to him.

Answer: D
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Re: Nicky and Cristina are running a 1,000 meter race. Since   [#permalink] 01 Jan 2020, 19:38
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