Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 29 Jan 2011
Posts: 237

Nicky and Cristina are running a 1,000 meter race. Since
[#permalink]
Show Tags
Updated on: 09 Sep 2012, 04:05
Question Stats:
58% (01:42) correct 42% (01:41) wrong based on 347 sessions
HideShow timer Statistics
Nicky and Cristina are running a 1,000 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? (A) 15 seconds (B) 18 seconds (C) 25 seconds (D) 30 seconds (E) 45 seconds
Official Answer and Stats are available only to registered users. Register/ Login.
Originally posted by siddhans on 06 Sep 2011, 23:59.
Last edited by Bunuel on 09 Sep 2012, 04:05, edited 1 time in total.
Renamed the topic and edited the question.



Manager
Joined: 04 Jun 2011
Posts: 124

Re: Nicky and Cristina
[#permalink]
Show Tags
07 Sep 2011, 00:09
ok.. im surprised by the answer...
nicky gets a headstart of 12 seconds.. and in this thime she runs 36 mts (12 * 3) and by the time christina starts, the gap between them is 36 mts
since christina is faster than nicky by 2 m/s she reduces the gap by 2 m/s
and therefore the whole gap is covered in 18 seconds... but the question is how much time nicky would have run before christina catches up
18 + 12 (the headstart nicky got) = 30
so i think the answer's got to be 30 or the question should be modified to not include the head start time
am i missing something?



Manager
Status: Still Struggling
Joined: 03 Nov 2010
Posts: 111
Location: India
GMAT Date: 10152011
GPA: 3.71
WE: Information Technology (Computer Software)

Re: Nicky and Cristina
[#permalink]
Show Tags
07 Sep 2011, 01:40
Wat's the confusion here? You are getting the correct ans, same as the OA.. Christina, being faster, runs for 18 secs. Nicki, runs for 30 secs.. ans is 30 secs..



Intern
Joined: 14 May 2011
Posts: 5

Re: Nicky and Cristina
[#permalink]
Show Tags
07 Sep 2011, 02:05
The distance traveled by both of them is the same at the time of overtaking.
3(t+12) = 5t
t=18.
Cristina will catch up Nicky in 18 seconds.
So in 18 seconds Cristina would cover = 18*5 = 90 meter.
Now Time taken my Nicky to cover 90 meter = 90/3 = 30 Seconds.
Hope this helps!



Manager
Joined: 04 Jun 2011
Posts: 124

Re: Nicky and Cristina
[#permalink]
Show Tags
07 Sep 2011, 07:17
krishnasty wrote: Wat's the confusion here? You are getting the correct ans, same as the OA.. Christina, being faster, runs for 18 secs. Nicki, runs for 30 secs.. ans is 30 secs.. ok.. the OA was changed.... when i first attepmted the problem, the OA was 18 sec



Senior Manager
Joined: 24 Jun 2012
Posts: 362
Location: Pakistan
Concentration: Strategy, International Business
GPA: 3.76

Re: Nicky and Cristina
[#permalink]
Show Tags
09 Sep 2012, 02:58
these questions are very easy to answer once they are logically understood. see Nicky rate of running is 3 meter/sec and he has 12 second head start. so after 12 seconds he has run 36 meters "(3)(12)". now the question tell us that Cristina runs at a pace of 5 meters per second. she is running 2 meter/second faster than nicky (53=2). simply divide the 36 meters with 2 you will get the answer. 36/2= 18 seconds.
_________________
Push yourself again and again. Don't give an inch until the final buzzer sounds. Larry Bird Success isn't something that just happens  success is learned, success is practiced and then it is shared. Sparky Anderson S



Manager
Joined: 24 Jul 2011
Posts: 61
Location: India
Concentration: Strategy, General Management
WE: Asset Management (Manufacturing)

Re: Nicky and Cristina
[#permalink]
Show Tags
09 Sep 2012, 04:49
sananoor wrote: these questions are very easy to answer once they are logically understood. see Nicky rate of running is 3 meter/sec and he has 12 second head start. so after 12 seconds he has run 36 meters "(3)(12)". now the question tell us that Cristina runs at a pace of 5 meters per second. she is running 2 meter/second faster than nicky (53=2). simply divide the 36 meters with 2 you will get the answer. 36/2= 18 seconds. Here, your answer 18 seconds is the time taken by Cristina. As Nicky has started 12 seconds early, total time taken by Nicky is 12+18 = 30 Seconds. So, the answer is D.



Senior Manager
Joined: 24 Jun 2012
Posts: 362
Location: Pakistan
Concentration: Strategy, International Business
GPA: 3.76

Re: Nicky and Cristina are running a 1,000 meter race. Since
[#permalink]
Show Tags
09 Sep 2012, 04:58
Exactly the answer is 30 by adding 18 and 12...i just mentioned that i am placing the logic behind this question to find that 18...thanks by the way... the other way one can do this question is Nicky: (RT= D) his rate is 3 meter/second and time= t+12sec therefore the distance he covered will be 3(t+12)1 Christina: (RT=D) her rate is 5 meter/second and time = t therefore the distance she covered will be 5t2 relating two distances 3(t+12) = 5t t = 18 putting the value of t for nicky t+12 = 18 + 12= 30 and thats the answer
_________________
Push yourself again and again. Don't give an inch until the final buzzer sounds. Larry Bird Success isn't something that just happens  success is learned, success is practiced and then it is shared. Sparky Anderson S



eGMAT Representative
Joined: 04 Jan 2015
Posts: 3158

Re: Nicky and Cristina are running a 1,000 meter race. Since
[#permalink]
Show Tags
01 Jun 2015, 22:41
In speed and distance questions drawing a diagram helps in visualizing the problem and easy formulation of the equation. Given InfoWe are given that Nicky runs at a speed of 3 meters/second for 12 seconds before Cristina starts running at a speed of 5 meters/second. We are asked to find the time for which Nicky has run before Cristina catches up with him. ApproachWe know that Distance = Speed * Time. Since we know the speed at which Nicky runs and his head start time we can calculate his head start distance. We also know the speed at which Cristina runs. Once Cristina starts running, they both will run for the same time before Cristina catches up with Nicky. Since we know the running speeds of both Nicky and Cristina, we can calculate their distance covered in terms of a common variable i.e. the time taken. As Nicky had a headstart, the extra distance covered by Cristina will be equal to the head start distance which Nicky had. Working OutRefer the below diagram Head start time given to Nicky = 12 seconds Speed at which Nicky runs = 3 meters/second Distance covered by Nicky = 12 * 3 = 36 meters Let the time taken by Cristina to catch up with Nicky be t. Speed at which Cristina runs = 5 meters/second Distance covered by Cristina in time t = 5t Distance covered by Nicky in time t = 3t Since distance covered by Cristina in time t is 36 meters more than that covered by Nicky in time t, we can write 5t = 3t + 36 i.e. t = 18 seconds. This is the time taken by Cristina to catch up with Nick. Since we are asked to find the time taken by Nicky, we will add the 12 seconds head start he had. So time for which Nicky ran before Cristina caught up with him = 18 + 12 = 30 seconds. Hope this helps Regards Harsh
_________________



Intern
Joined: 06 Nov 2016
Posts: 25

Re: Nicky and Cristina are running a 1,000 meter race. Since
[#permalink]
Show Tags
27 Jul 2017, 13:07
siddhans wrote: Nicky and Cristina are running a 1,000 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
(A) 15 seconds (B) 18 seconds (C) 25 seconds (D) 30 seconds (E) 45 seconds I guess the total distance is irrelevant here. Relative Speed is 5  3 = 2 mps. Distance traveled by Cristina in 12 seconds is 36 meters. So, Nicky will have to catch up 12 * 3 = 36 meters at a speed of 2 mps. Nicky will catch up in 18 sec. Christina would have traveled 18 + 12 = 30 seconds.



Intern
Joined: 06 Nov 2016
Posts: 25

Re: Nicky and Cristina are running a 1,000 meter race. Since
[#permalink]
Show Tags
27 Jul 2017, 13:08
siddhans wrote: Nicky and Cristina are running a 1,000 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
(A) 15 seconds (B) 18 seconds (C) 25 seconds (D) 30 seconds (E) 45 seconds I guess the total distance is irrelevant here. Relative Speed is 5  3 = 2 mps. Distance traveled by Cristina in 12 seconds is 36 meters. So, Nicky will have to catch up 12 * 3 = 36 meters at a speed of 2 mps. Nicky will catch up in 18 sec. Christina would have traveled 18 + 12 = 30 seconds.



NonHuman User
Joined: 09 Sep 2013
Posts: 13727

Re: Nicky and Cristina are running a 1,000 meter race. Since
[#permalink]
Show Tags
01 Oct 2018, 02:21
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________




Re: Nicky and Cristina are running a 1,000 meter race. Since
[#permalink]
01 Oct 2018, 02:21






