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Re: Of the marbles in a box, 2/5 are blue, 1/3 are red, and the rest are [#permalink]
Here's how I solved it.

First, put it into like terms that are easily divisible using a common multiple. Usually people use the LCM, but in this case it was easier for me to play with numbers at a higher multiple (30). Also, make note that half of the marbles are large.

2x/5x for blue and 1x/3x for red means that 4x/15x marbles are green. Convert these into easy numbers --> 12x/30x, 10x/30x and 8x/30x. Now let's move onto the statements.

1) Half of the blue and red marbles are large. so 6x blue and 5x red marbles are large. since in total this amounts to 11x/30x, the remaining large marbles must be 4x/30 of the green ones (since adding these together gives a value of 15x/30x which is half the marbles, whatever the value).

At this point, we can't solve for the number of marbles, but you have 3 ratios for the number of large marbles in the box based on colour. Moving on to statement 2.

2) okay, so R + G = 36 large marbles, here R = ratio of red marbles that are large, and G = equals ratio of green marbles that are large. Great. We don't know what the ratios are from the question stem, so we definitely can't answer the question using statement 2 alone.

Looking at both statements together, we can combine the ratios to get to an answer. We know that half of the red marbles are large (5x/30) and that 4x/30 of the green marbles are large. Let's plug that into the equation from statement 2.

(5x+4x)/30 = 36 --> solving for x, we know that the total number of marbles is 120. Sufficient!
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Re: Of the marbles in a box, 2/5 are blue, 1/3 are red, and the rest are [#permalink]
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Re: Of the marbles in a box, 2/5 are blue, 1/3 are red, and the rest are [#permalink]
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