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On the xy-coordinate plane, what is the area of a triangle with vertic
[#permalink]
03 Feb 2017, 04:57
03 Feb 2017, 04:57
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Difficulty:
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Question Stats:
79% (01:45) correct
21%
(02:14)
wrong
based on 246
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On the xy-coordinate plane, what is the area of a triangle with vertices at (-4, -3), (5, -3), and (-2, -7) ?
(A) 4
(B) 9
(C) 12
(D) 18
(E) 36
(A) 4
(B) 9
(C) 12
(D) 18
(E) 36
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Joined: 12 Sep 2015
Posts: 6804
Given Kudos: 799
Location: Canada
Re: On the xy-coordinate plane, what is the area of a triangle with vertic
[#permalink]
03 Feb 2017, 08:27
03 Feb 2017, 08:27
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SajjadAhmad wrote:
On the xy-coordinate plane, what is the area of a triangle with vertices at (-4, -3), (5, -3), and (-2, -7) ?
(A) 4
(B) 9
(C) 12
(D) 18
(E) 36
(A) 4
(B) 9
(C) 12
(D) 18
(E) 36
Sketch the triangle and make the horizontal line the base.
The length of the base will equal the difference in x-coordinates: 5 - (-4) = 9
The height of the triangle will equal the difference in y-coordinates: (-3) - (-7) = 4
Area = (base)(height)/2
= (9)(4)/2
= 18
Answer: D
General Discussion
Re: On the xy-coordinate plane, what is the area of a triangle with vertic
[#permalink]
03 Feb 2017, 05:08
03 Feb 2017, 05:08
2
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Expert Reply
SajjadAhmad wrote:
On the xy-coordinate plane, what is the area of a triangle with vertices at (-4, -3), (5, -3), and (-2, -7) ?
(A) 4
(B) 9
(C) 12
(D) 18
(E) 36
(A) 4
(B) 9
(C) 12
(D) 18
(E) 36
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Hope it helps.
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