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In the rectangular coordinate system, the vertices of a triangle have
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01 Mar 2015, 16:26
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In the rectangular coordinate system, the vertices of a triangle have coordinates (3,0), (3,2), and (0,11). What is the area of the triangle. 1.15 2.18 3.24 4.30 5.36
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Re: In the rectangular coordinate system, the vertices of a triangle have
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02 Mar 2015, 00:03
Turkish wrote: In the rectangular coordinate system, the vertices of a triangle have coordinates (3,0), (3,2), and (0,11). What is the area of the triangle.
1.15 2.18 3.24 4.30 5.36 hi turkish, you can find the length of three sides.. 1)\(\sqrt{( (33)^2+(02)^2)}\)=\(\sqrt{40}\) say side A 2)\(\sqrt{( (30)^2+(011)^2)}\)=\(\sqrt{130}\) say side B 3)\(\sqrt{( (30)^2+(211)^2)}\)=\(\sqrt{90}\).. say side C now you can see A^2 + c^2 = B^2... this means there is a right angle between sides A and C.. so area=1/2*A*C=1/2*\(\sqrt{40}\)*\(\sqrt{90}\)=30.. ans D...
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Re: In the rectangular coordinate system, the vertices of a triangle have
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02 Mar 2015, 00:12
Hi Turkish, I'm going to offer some suggestions so that you can physically attempt this question on your own: 1) Draw a quick graph/sketch and plot those 3 coordinates. Connect the coordinates with lines. The graph doesn't have to be perfect. 2) Draw a rectangle "around" this triangle. Your rectangle should have the following 4 corners: (3,0), (3,0), (3,11), (3,11) 3) You should see your original triangle and 3 right triangles. 4) Figure out the area of the rectangle and subtract the areas of the 3 right triangles. This will give you the area of the original triangle. GMAT assassins aren't born, they're made, Rich
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Re: In the rectangular coordinate system, the vertices of a triangle have
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15 Jan 2016, 13:51
Approximate by supposing that the vertex (3,2) is on the xaxis forming an isosceles triangle: (3,2) > (something>3;0)
Then, the area of this approximate isosceles triangle would be 6*11/2 = 33 The area of the actual triangle must be a little bit less than that of the approximate triangle. Thus 30, answer D.



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Re: In the rectangular coordinate system, the vertices of a triangle have
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23 Apr 2017, 13:32
Here is an alternate and a bit easier approach provide you know how to solve a 3x3 matrix => USE THE DETERMINANT METHOD. Area of a triangle => 1/2Determinant Value
Lets get the determinant of the matrix =>
1 3 0 1 3 2 1 0 11
Determinant => 1(33)  (3)(112) + 0(03) => 33+27=60
Hence the area of the triangle => 1/2 * 60 => 30
SMASH THAT D.
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Re: In the rectangular coordinate system, the vertices of a triangle have
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26 Apr 2017, 01:40
area of triangle = ½ y₁ (x₂  x₃) + y₂ (x₃  x₁) + y₃ (x₁  x₂) =1/2 { 27 + 33} =30



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Re: In the rectangular coordinate system, the vertices of a triangle have
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15 May 2017, 13:22
Using Matrix Method 3 0 1  3 2 1  0 11 1 3(211)+33=60 taking half of matrix=30
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Re: In the rectangular coordinate system, the vertices of a triangle have
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16 May 2017, 00:51
1/2 ( 3(211)+3(110)+0(02)) = 30




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