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27 Mar 2015, 05:25
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
79% (01:51) correct
21%
(02:41)
wrong
based on 324
sessions
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If a triangle in the xy-coordinate system has vertices at (-2 , -3), (4, -3) and (28, 7), what is the area of the triangle?
A. 30
B. 36
C. 48
D. 60
E. 65
Kudos for a correct solution.
A. 30
B. 36
C. 48
D. 60
E. 65
Kudos for a correct solution.
30 Mar 2015, 03:53
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Bunuel
MAGOOSH OFFICIAL SOLUTION:
Attachment:
areaoftriangle_text.PNG [ 16.56 KiB | Viewed 13361 times ]
General Discussion
27 Mar 2015, 05:34
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Let's say A is (-2,-3), B is (4,-3) and C is (28,7).
If we quickly plot A, B and C on co-ordinate system, it's obvious that A and B are parallel to x-axis. So, length of AB is 6.
Let AB be the base, then height of triangle will be length of perpendicular from C on AB. But since AB is parallel to x-axis, it'll be just (7-(-3)) = 10.
So area = (1/2)*6*10.
If we quickly plot A, B and C on co-ordinate system, it's obvious that A and B are parallel to x-axis. So, length of AB is 6.
Let AB be the base, then height of triangle will be length of perpendicular from C on AB. But since AB is parallel to x-axis, it'll be just (7-(-3)) = 10.
So area = (1/2)*6*10.
