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Re: At his regular hourly rate, Don had estimated the labor cos [#permalink]
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Rdotyung wrote:
Bunuel wrote:
macjas wrote:
At his regular hourly rate, Don had estimated the labour cost of a repair job as $336 and he was paid that amount. However, the job took 4 hours longer than he had estimated and, consequently, he earned $2 per hour less than his regular hourly rate. What was the time Don had estimated for the job, in hours?

(A) 28
(B) 24
(C) 16
(D) 14
(E) 12


On my own I got to the step where I need to utilize the answer choices. I didn't know what to do at that point because it never crosses my mind to use the answer choices and backwards solve like this.

I've only ever seen this kind of method recommended when the problem involves second degree equations. Is that a fair statement? You only backwards solve like this when dealing with second degree equations?


You utilize the answer choices whenever you CAN. Here I would keep an eye on the choices right from the start. I would say
R*T = 336 (his regular hourly rate * time he estimated)
The options give us the value of T which is an integer.

\(336 = 2^4*3*7\)

So R*T = 336
(R-2)*(T + 4) = 336
So T as well as T+4 should be factors of 336.
If T is 28, T+4 is 32 which is not a factor of 336 so ignore it.
If T is 24, T+4 is 28. Both are factors of 336. Keep it. If T is 24, R is 14. So (R - 2) is 12. 12*28 does gives us 336 so T = 24 must be the correct answer.

But note that if you want to reduce your mechanical work, you need to be fast in your calculations. You cannot spend a minute working on every option or making calculation mistakes.
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Re: At his regular hourly rate, Don had estimated the labor cos [#permalink]
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[336][/X] - [336][/(X+4)]= 2

Solve for X.

Ans= 24 since -28 is not a valid answer.
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At his regular hourly rate, Don had estimated the labor cos [#permalink]
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macjas wrote:
At his regular hourly rate, Don had estimated the labour cost of a repair job as $336 and he was paid that amount. However, the job took 4 hours longer than he had estimated and, consequently, he earned $2 per hour less than his regular hourly rate. What was the time Don had estimated for the job, in hours?

(A) 28
(B) 24
(C) 16
(D) 14
(E) 12

STRATEGY: Upon reading any GMAT Problem Solving question, we should always ask, Can I use the answer choices to my advantage?
In this case, we can easily test the answer choices.
Now let's give ourselves up to 20 seconds to identify a faster approach.
In this case, we can also follow the conventional algebraic approach, but I think testing answer choices will be faster (and less prone to algebraic errors)


GMAT-specific approach: Testing the answer choices
Let’s start by testing answer choice C, the middle value. . .
(C) 16. This tells us that Don originally estimated the job would take 16 hours.
Hourly rate = (total labor cost)/(number of hours worked) = $336/16 = $21/hour
If the job took 4 extra hours, then Don worked 20 hours, which means his actual hourly rate = $336/20 = 84/5 = $16.80/hour (check out the video below on dividing numbers by 5 in your head)
$21/hour - $16.80/hour$4 per hour

So, testing choice C resulted in a rate difference of approximately $4 per hour, whereas the question tells us the rate difference is only $2 per hour.
This bigger-than-needed difference tells us that Don’s estimated work time must have been more than 16 hours, since this would reduce the effect of the 4 extra hours (and thus a smaller difference).
Since we need Don's estimated work time to be more than 16 hours, we can eliminate answer choices C, D, and E.

Now let’s test choice B. . . .
(B) 24. This tells us that Don originally estimated the job would take 24 hours.
Estimated hourly rate = $336/24 = $14/hour
If the job took 4 extra hours, then Don worked 28 hours, which means his actual hourly rate = $336/28 = $12/hour
So, the difference in hourly rates = $14/hour - $12/hour = $2/hour. Perfect!!

Answer: B.

Conventional approach: Assign variables, create equation, solve equation
Let h = # of hours that Don ESTIMATED for the job.
So, h + 4 = ACTUAL # of hours it took Don to complete the job.

Hourly rate = (total labor cost)/(number of hours worked)
So, IF Don, had completed the job in h hours, his RATE would have been $336/h
However, since Don completed the job in h+4 hours, his RATE was actually $336/(h + 4)

...consequently, he earned 2$ per hour less than his regular hourly rate.
In other words, (John's estimated rate) - 2 = (John's actual rate)
So, we can substitute values to get: $336/h - 2 = $336/(h + 4)

IMPORTANT: Since the above equation will be a pain to solve, you might consider plugging in the answer choices to see which one works.

Okay, let's solve this thing: $336/h - 2 = $336/(h + 4)
To eliminate the fractions, multiply both sides by (h)(h+4) to get: 336(h+4) - 2(h)(h+4) = 336h
Expand: 336h + 1344 - 2h² - 8h = 336h
Simplify: -2h² - 8h + 1344 = 0
Multiply both sides by -1 to get: 2h² + 8h - 1344 = 0
Divide both sides by 2 to get: h² + 4h - 672 = 0
Factor (yeeesh!) to get: (h - 24)(h + 28) = 0
Solve to get: h = 24 or h = -28
Since h cannot be negative (in the real world), h must equal 24.

Answer: B

RELATED VIDEO - Shortcut for Dividing by 5

Originally posted by BrentGMATPrepNow on 28 Aug 2017, 14:26.
Last edited by BrentGMATPrepNow on 13 Apr 2022, 12:37, edited 1 time in total.
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Re: At his regular hourly rate, Don had estimated the labor cos [#permalink]
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macjas wrote:
At his regular hourly rate, Don had estimated the labour cost of a repair job as $336 and he was paid that amount. However, the job took 4 hours longer than he had estimated and, consequently, he earned $2 per hour less than his regular hourly rate. What was the time Don had estimated for the job, in hours?

(A) 28
(B) 24
(C) 16
(D) 14
(E) 12


To solve this problem we can translate the problem with the given information into an equation. Since we don’t know Don's hourly rate nor the time he had estimated for the job, we use two variables:

w = Don’s hourly rate

t = number of hours he estimated for the job

We are given that Don was paid $336, based on his original estimate, so we can say:

w x t = 336

Next we are given that the job took 4 hours longer and that, as a result, he earned 2 dollars less than his regular rate. This leads us to say:

(w – 2)(t + 4) = 336

We rewrite the equation w x t = 336 as w = 336/t. Now we substitute 336/t for w in the equation (w – 2)(t + 4) = 336. Thus, we have:

[(336/t) – 2](t + 4) = 336

After FOILing we have:

336 + (4x336)/t – 2t – 8 = 336

(4x336)/t – 2t – 8 = 0

Multiplying the entire equation by t, we get:

4 x 336 – 2t^2 – 8t = 0

Dividing the entire equation by 2, we get:

2 x 336 – t^2 – 4t = 0 or 672 – t^2 – 4t = 0

We can also rewrite this as: t^2 + 4t – 672 = 0

Now this is where we should be strategic with our answer choices. To solve this quadratic we are looking for two numbers that sum to a positive 4 and multiply to a negative 672. Our answer choices are:

(A) 28
(B) 24
(C) 16
(D) 14
(E) 12

There are only two pairs of answer choices that are 4 units apart: 16 and 12, and 28 and 24. Since 24 multiplied by 28 is 672, we know that the numbers that are needed for the factoring are 24 and 28. Thus, we can say:

(t – 24)(t + 28) = 0

We can see that t = 24 or t = -28. However, since we can’t have a negative number of hours, only t = 24 is the correct answer.

Answer B
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Re: At his regular hourly rate, Don had estimated the labor cos [#permalink]
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Hi All,

We’re told that Don was paid $336 for an hourly-rate for a job that he estimated would take a certainly number of hours. However, the job took 4 hours LONGER than estimated, which means he was actually paid $2/hour LESS than his normal hourly-rate for the job. We’re asked for the original number of hours that Don estimated the job would take. This question can be approached in a couple of different ways, including by TESTing THE ANSWERS.

Since the extra 4 hours spent working only decreased his normal hourly-rate by $2/hour for the job, we should start by TESTing one of the larger numbers (since the smaller the ratio of 4 hours to the original estimated time, the less impact that 4 hours would have on the average). Let’s TEST Answer B…

Answer B: 24 hours.

IF… the original estimate was 24 hours to complete the job, then Don’s hourly pay would have been $336/24 = 14 dollars/hour.

The extra 4 hours would increase the total time to 24+4 = 28 hours. In this situation, Don’s hourly pay would have been $336/28 = 12 dollars/hour. This is an exact MATCH for what we were told, so this MUST be the answer.

Final Answer:

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Re: At his regular hourly rate, Don had estimated the labor cos [#permalink]
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Solution:

Let us assume that the regular charges that John actually had was x dollars,

Let the estimate of the time that he intended for this particular job = y hours,

=>x y =36

But however, there is a little change because the job took four hours longer

So, its y+4 now and it no longer is x$ ,rather (x-2)

(x -2)(y+4)=336

=>(x-2) (y+4) = x y(Both equal 336)

=>x y + 4x -2y – 8 = x y

=> y = 2x-4 …….(1)

Now plug in the options (for y) and check where you get x y =336

At Y=24 (option B) x= y+4/2(from 1) = 14

X y= 14 x 24 = 336 .

option(b)

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I have just worked on OG Math practice questions and hardly have I solved this question. That's why I have used Google and found you guys :)
sayak636 wrote:
[336][/X] - [336][/(X+4)]= 2
I have composed the same equation, however its solving has taken me for ages.

I like Bunuel's solution, but I has not guessed to do the same. I'd only slightly change the course of solving. When we get to \(t = 2r - 4\), \(r\) easily seems to be replaced by \(336/t\). Now we have \(t = (2*336/t) - 4\) and can plug answer choices to find out the correct option.
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While substitution does tend to take long for this problem, before substitution you could
factorize 336 to its primes = 2*2*2*2*3*7


Now you can begin to substitute : Ans
Choice A = 28*12 (2*2*7*2*2*3) not equal to 32*10 (clearly its 320 and not 336)
Choice B = 24*14 (2*2*2*3*2*7) equals 28*12 (from prev choice)

thx
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Shiv636 wrote:
[336][/X] - [336][/(X+4)]= 2

Solve for X.

Ans= 24 since -28 is not a valid answer.


Infact, one doesn't need to solve after this step too:

\(\frac{336}{x} - \frac{336}{(x+4)} = 2\)

336[(x+4)-x] = 2*x(x+4)

x(x+4) = 672

From the given options, we can straightaway eliminate A and C, as because the units digit after multiplication of 28*(28+4) and 16*(16+4) will never be 2.

We also know that 14*20 = 280 and 12*20 = 240. Thus, 14*18(D) or 12*16(E) can never equal 672.

By eliminaion, the answer is B.
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Re: At his regular hourly rate, Don had estimated the labor cos [#permalink]
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Bunuel wrote:
macjas wrote:
At his regular hourly rate, Don had estimated the labour cost of a repair job as $336 and he was paid that amount. However, the job took 4 hours longer than he had estimated and, consequently, he earned $2 per hour less than his regular hourly rate. What was the time Don had estimated for the job, in hours?

(A) 28
(B) 24
(C) 16
(D) 14
(E) 12


Say the regular hourly rate was \(r\)$ and estimated time was \(t\) hours, then we would have:

\(rt=336\) and \((r-2)(t+4)=336\);

So, \((r-2)(t+4)=rt\) --> \(rt+4r-2t-8=rt\) --> \(t=2r-4\).

Now, plug answer choices for \(t\) and get \(r\). The pair which will give the product of 336 will be the correct answer.

Answer B fits: if \(t=24\) then \(r=14\) --> \(rt=14*24=336\).

Answer: B.

Hope it's clear.


On my own I got to the step where I need to utilize the answer choices. I didn't know what to do at that point because it never crosses my mind to use the answer choices and backwards solve like this.

I've only ever seen this kind of method recommended when the problem involves second degree equations. Is that a fair statement? You only backwards solve like this when dealing with second degree equations?
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Re: At his regular hourly rate, Don had estimated the labor cos [#permalink]
How do you go from

> 336[(x+4)-x] = 2*x(x+4)
to > x(x+4) = 672?
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gciftci wrote:
How do you go from

> 336[(x+4)-x] = 2*x(x+4)
to > x(x+4) = 672?



\(336 * [(x+4)-x] = 2 * x * (x+4)\)

\(336 * [x+4 -x] = 2 * x * (x+4)\)

x and -x get cancelled to give:

\(336 * [4] = 2 * x * (x+4)\)

Divide both sides by 2.
\(336 * 2 = x * (x+4)\)

\(672 = x * (x+4)\)
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Re: At his regular hourly rate, Don had estimated the labor cos [#permalink]
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VeritasPrepKarishma wrote:

On my own I got to the step where I need to utilize the answer choices. I didn't know what to do at that point because it never crosses my mind to use the answer choices and backwards solve like this.

I've only ever seen this kind of method recommended when the problem involves second degree equations. Is that a fair statement? You only backwards solve like this when dealing with second degree equations?
[/quote]

You utilize the answer choices whenever you CAN. Here I would keep an eye on the choices right from the start. I would say
R*T = 336 (his regular hourly rate * time he estimated)
The options give us the value of T which is an integer.

\(336 = 2^4*3*7\)

So R*T = 336
(R-2)*(T + 4) = 336
So T as well as T+4 should be factors of 336.
If T is 28, T+4 is 32 which is not a factor of 336 so ignore it.
If T is 24, T+4 is 28. Both are factors of 336. Keep it. If T is 24, R is 14. So (R - 2) is 12. 12*28 does gives us 336 so T = 24 must be the correct answer.

But note that if you want to reduce your mechanical work, you need to be fast in your calculations. You cannot spend a minute working on every option or making calculation mistakes.[/quote]

Hi Karishma, Why do T and T+4 have to be factors of 336? Why cannot rate be a fraction and difference of two fractions can yield an integer in this case 2? What am I missing here? Thanks!
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MensaNumber wrote:

Hi Karishma, Why do T and T+4 have to be factors of 336? Why cannot rate be a fraction and difference of two fractions can yield an integer in this case 2? What am I missing here? Thanks!


All the options are integers so value of T must be an integer. So T+4 must be an integer too. Therefore, T and T+4 must be factors of 336. Also, in GMAT, usually numbers are easy since you do not get calculators. So very rarely will you find that rate or time is a fraction. Even if it will be, it will be a simple fraction such as 1/2 etc.
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Hi RussianDude,

You're not expected to answer every question in the Quant section in under 2 minutes, so if you took a little longer than that on this question, then that's fine (as long as you were doing work and not staring at the screen). If you took more than 3 minutes to answer this question, then chances are that YOUR approach is the "long" approach and that you have to practice other tactics.

Here, since the answer choices ARE numbers, we're really looking for an answer that divides into 336 AND when you add 4 to that answer, that sum ALSO divides evenly into 336. The difference between those two rates should be $2 (as the question states). In that way, you can answer this question with some basic division and note-taking (and likely save time and avoid a long-winded Algebra approach).

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Re: At his regular hourly rate, Don had estimated the labor cos [#permalink]
Can someone correct me?

336=xh
h=336/x

(h+4)=336/2x
xh+4x=168
4x=168-336
x=42

:( :( :( :( :(
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Hi paidlukkha,

You can certainly treat this prompt as a 'system' question (2 variables and 2 unique equations.

Your first equation is correct:

336 = (X)(H)

However, your second equation is NOT. Since the number of hours increases by 4 and the difference in hourly pay is 2, the equation should be...

336 = (X - 2)(H + 4)

From here, you can proceed with the Algebra and you'll get to the solution.

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